What is #, is it 1, 2, 3??
Okay Let's say
2x + 3 = 45
-3 -3
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2x = 42
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2 2 x = 21
To find equivalent expressions, distribute the 7 into (-3/4x - 3)
7(-3/4x) = -21/4x, which simplified is -5 1/4x
7(-3) = -21
Put together, this is -5 1/4x - 21 (answer 1)
Another way to write an equivalent expression would be to not simplify 7 times the distributed term. You could write 7(-3/4) + 7(-3) which makes #5 correct as well. #5 is 7(-3/4x) - 7(3). If this was simplified, it would equal answer choice 1.
#2 is not correct because 7 times -3/4x does not equal -7 3/4x
#3 is not correct because -21/4 simplifies to -5 1/4, not -6 1/4
#4 is not correct because 7(-3) does not equal -4
Answer:
k = ln (6/5)
Step-by-step explanation:
for
f(x)=A*exp(kx)+B
since f(0)=1, f(1)=2
f(0)= A*exp(k*0)+B = A+B = 1
f(1) = A*exp(k*1)+B = A*e^k + B = 2
assuming k>0 , the horizontal asymptote H of f(x) is
H= limit f(x) , when x→ (-∞)
when x→ (-∞) , limit f(x) = limit (A*exp(kx)+B) = A* limit [exp(kx)]+B* limit = A*0 + B = B
since
H= B = (-4)
then
A+B = 1 → A=1-B = 1 -(-4) = 5
then
A*e^k + B = 2
5*e^k + (-4) = 2
k = ln (6/5) ,
then our assumption is right and k = ln (6/5)
