“Times as fast” means you need to multiply the original speed (10^11) by how many times faster the faster processor works:
10^11 instructions/second • 10^3 faster = 10^14 instructions/second
The key is “___ times as fast”.
Y is increased by 6 because if you imagine x being 3 then y would = 16 but if you increase x by 3 making 6 then y would = 22 and 16 increased by 6 is 22
To find c, you must isolate it.
To do this, you must divide both sides by 5/7, since that is being multiplied by c and you must do the inverse to it to cancel it out in order to leave c by itself.
5/7c ÷ 5/7 = c
13/14 ÷ 5/7
To divide fractions, follow these steps:
Step 1- Turn the second fraction, 5/7 in this case, into its reciprocal. This means swapping the places of the numerator and denominator.
5/7 reciprocal = 7/5
Step 2- multiply the original first fraction and reciprocal second fraction.
13/14 • 7/5
13 • 7 = 91
14 • 5 = 70
13/14 ÷ 5/7 = 91/70
Step 3- Simplify if possible.
91/70
Since 70 can go into 90, you can turn this into a mixed number.
1 and 21/70
Now simplify 21/70.
Both can be divided by 7.
21 ÷ 7 = 3
70 ÷ 7 = 10
So simplified, 91/70 equals 1 and 3/10.
As a decimal, this is 1.3.
So the answer is c = 1.3, or 1 and 3/10.
Hope this helps :)
Answer:
A would be 150 times.
Step-by-step explanation:
I can't see the options for Part B so i cant help with that sorry. I think A would be 150 times though because with numbers 1-10, half of them are even and half of them are odd and half of 300 is 150.
