Answer:
The largest number of pyramids she can make from 20 bars of chocolate is:
Step-by-step explanation:
Firstly, you must find the volume of the 20 bars of chocolate, remember that each bar contains 6 cubic inches of chocolate (6 in^3), so:
- Volume of the bars = 6 in^3 * 20
- <u>Volume of the bars = 120 in^3</u>
Now, you must find the volume of each pyramid, using the next formula:
- Volume of a pyramid = 1/3 B * h
Where:
<em>B = area of the square base.</em>
<em>h = height of the pyramid.</em>
How these values are given in the problem, we only replace the values in the formula:
- Area of a pyramid = 1/3 (1 in^2) * 2 in
- <u>Area of a pyramid = 2/3 in^3</u>
Finally, we divide the volume of the bars in the volume of each pyramid:
- Total number of pyramids = 120 in^3 / 2/3 in^3
- <u>Total number of pyramids = 180</u>
Answer:
Step-by-step explanation:
Hello!
Your study variable is X: "number of ColorSmart-5000 that didn't need repairs after 5 years of use, in a sample of 390"
X~Bi (n;ρ)
ρ: population proportion of ColorSmart-5000 that didn't need repairs after 5 years of use. ρ = 0.95
n= 390
x= 303
sample proportion ^ρ: x/n = 303/390 = 0.776 ≅ 0.78
Applying the Central Limit Theorem you approximate the distribution of the sample proportion to normal to obtain the statistic to use.
You are asked to estimate the population proportion of televisions that didn't require repairs with a confidence interval, the formula is:
^ρ±
* √[(^ρ(1-^ρ))/n]
= 
= 2.58
0.78±2.58* √[(0.78(1-0.78))/390]
0.0541
[0.726;0.834]
With a confidence level of 99% you'd expect that the interval [0.726;0.834] contains the true value of the proportion of ColorSmart-5000 that didn't need repairs after 5 years of use.
I hope it helps!
Answer:
to find range of interquartile sets of data
you see 5 vertical lines 1 is start point 2 is start of 2nd quartile 3 is start of 3rd quartile and also represents the median. the 4th start of 4th quartile and 5th is very end point.
Therefore the interquartile is from start line 2 to start line 4
apply to each by if it says 10 and 34 then we show workjings 34-10 = 24 and that is the range once we deduct data from each other.
Therefore full range is start line 1 to end line 5
if this says 2 to 45 then full range is 45-2 = 43 and apply to each boxplot.
Step-by-step explanation:
Answer:
The volume of the cone is;
100 π inches^3
Step-by-step explanation:
To calculate the volume, we need the height
We can get the height from the slant height and the radius
Mathematically, we use Pythagoras’ theorem for this as the slant height, the radius and the height forms a right-angled triangle
The right-angled triangle has the slant height as its hypotenuse
By the theorem, the square of the hypotenuse equals the sum of the squares of the two other sides
Let the height be h
Thus;
12^2 = 5^2 + h^2
169= 25 + h^2
h^2 = 169-25
h^2 = 144
h = √1144 inches = 12 inches
The volume of the cone is;
1/3 * π * r^2 * h
= 1/3 * π * 5^2 * 12
= 100 π inches^3
Answer:
The base is 19.5.
Step-by-step explanation:
The given question is, "The perimeter of a rectangle is 58 and its base exceeds its width by 10, how long is the base?"
Perimeter = 58
Base, l = 10+b
The perimeter of a rectangle is :
P = 2(l+b)
58 = 2(10+b+b)
29 = (10+2b)
29-10 = 2b
19 = 2b
b = 9.5
Base, l = 10 + 9.5
= 19.5
Hence, the base is 19.5.
