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3 years ago

8

WILL GIVE BRAINIEST Mr. Wright wants to tile a 5 ft by 5 ft square floor. He has three kinds of square tiles: 1 ft by 1 ft, 2 ft

by 2 ft, and 3 ft by 3 ft. Tiles may not overlap or be cut. What is the fewest tiles Mr. Wright may use to completely cover his floor?

1 answer:

BlackZzzverrR [31]3 years ago

8 0

Answer:

h

Step-by-step explanation:

h

You might be interested in

P(x)=3x 4 −2x 3 +2x 2 −1P, left parenthesis, x, right parenthesis, equals, 3, x, start superscript, 4, end superscript, minus, 2

Oksanka [162]

The remainder when the polynomial is divided by x + 1 is 2

Given the function P(x)=3x^4 −2x^3 +2x^2 −1, to get the rmainder if the polynomial is divided by x + 1, we will substitute x = - 1 into the function to have:

P(-1) = 3(-1)^4 −2(-1)^3 +2(-1)^2 −1

P(-1) = 3(1) - 2 + 2(1) - 1

P(-1) = 1 + 1

P(-1) = 2

Hence the remainder when the polynomial is divided by x + 1 is 2

Learn more on polynomials here: brainly.com/question/4142886

3 0

2 years ago

Consider the simple linear regression model Yi=β0+β1xi+ϵi, where ϵi's are independent N(0,σ2) random variables. Therefore, Yi is

Virty [35]

Answer:

See proof below.

Step-by-step explanation:

If we assume the following linear model:

$y = \beta_o + \beta_1 X +\epsilon$

And if we have n sets of paired observations $(x_i, y_i) , i =1,2,...,n$ the model can be written like this:

$y_i = \beta_o +\beta_1 x_i + \epsilon_i , i =1,2,...,n$

And using the least squares procedure gives to us the following least squares estimates $b_o$ for $\beta_o$ and $b_1$ for $\beta_1$ :

$b_o = \bar y - b_1 \bar x$

$b_1 = \frac{s_{xy}}{s_xx}$

Where:

$s_{xy} =\sum_{i=1}^n (x_i -\bar x) (y-\bar y)$

$s_{xx} =\sum_{i=1}^n (x_i -\bar x)^2$

Then $\beta_1$ is a random variable and the estimated value is $b_1$ . We can express this estimator like this:

$b_1 = \sum_{i=1}^n a_i y_i$

Where $a_i =\frac{(x_i -\bar x)}{s_{xx}}$ and if we see careful we notice that $\sum_{i=1}^n a_i =0$ and $\sum_{i=1}^n a_i x_i =1$

So then when we find the expected value we got:

$E(b_1) = \sum_{i=1}^n a_i E(y_i)$

$E(b_1) = \sum_{i=1}^n a_i (\beta_o +\beta_1 x_i)$

$E(b_1) = \sum_{i=1}^n a_i \beta_o + \beta_1 a_i x_i$

$E(b_1) = \beta_1 \sum_{i=1}^n a_i x_i = \beta_1$

And as we can see $b_1$ is an unbiased estimator for $\beta_1$

In order to find the variance for the estimator $b_1$ we have this:

$Var(b_1) = \sum_{i=1}^n a_i^2 Var(y_i) +\sum_i \sum_{j \neq i} a_i a_j Cov (y_i, y_j)$

And we can assume that $Cov(y_i,y_j) =0$ since the observations are assumed independent, then we have this:

$Var (b_1) =\sigma^2 \frac{\sum_{i=1}^n (x_i -\bar x)^2}{s^2_{xx}}$

And if we simplify we got:

$Var(b_1) = \frac{\sigma^2 s_{xx}}{s^2_{xx}} = \frac{\sigma^2}{s_{xx}}$

And with this we complete the proof required.

8 0

4 years ago

Which of the following is the point and slope of the equation y - 3 = (x - 5)?

Ilia_Sergeevich [38]

<u>ANSWER: </u>

The slope of the given line y - 3 = (x - 5) is 1 and (5, 3) is a point on that line.

<u>SOLUTION: </u>

Given, line equation is y – 3 = (x – 5)

We have to find the slope of the given equation along with a point on that line.

Now, if we observe, the given equation is in point slope form $y-y_{1}=m\left(x-x_{1}\right)$

Where, m is the slope of the line and $\left(x_{1}, y_{1}\right)$ is a point on the line.

Now by comparison of the two equations we can conclude that,

$\mathrm{m}=1 , x_{1}=5 \text { and } y_{1}=3$

So, the point on the given line is (5, 3).

Hence, the slope of the given line is 1 and (5, 3) is a point on that line.

8 0

3 years ago

Round $4.39 to the nearest dollar

pshichka [43]

It would be 4 dollars

8 0

3 years ago

What is the value of x

liubo4ka [24]

Answer:

x = 73°

Step-by-step explanation:

a whole circle = 360°

so x + 50° + 91° + 2x = 360°

x+ 2x = 360°- 91° - 50°

3x = 219°

x = 219° ÷ 3

x = 73°

<h2>HOPE THIS HELP YOU!!! ;))))</h2>

7 0

4 years ago

Read 2 more answers