P(x)=3x 4 −2x 3 +2x 2 −1P, left parenthesis, x, right parenthesis, equals, 3, x, start superscript, 4, end superscript, minus, 2
Oksanka [162]
The remainder when the polynomial is divided by x + 1 is 2
Given the function P(x)=3x^4 −2x^3 +2x^2 −1, to get the rmainder if the polynomial is divided by x + 1, we will substitute x = - 1 into the function to have:
P(-1) = 3(-1)^4 −2(-1)^3 +2(-1)^2 −1
P(-1) = 3(1) - 2 + 2(1) - 1
P(-1) = 1 + 1
P(-1) = 2
Hence the remainder when the polynomial is divided by x + 1 is 2
Learn more on polynomials here: brainly.com/question/4142886
Answer:
See proof below.
Step-by-step explanation:
If we assume the following linear model:

And if we have n sets of paired observations
the model can be written like this:

And using the least squares procedure gives to us the following least squares estimates
for
and
for
:


Where:


Then
is a random variable and the estimated value is
. We can express this estimator like this:

Where
and if we see careful we notice that
and 
So then when we find the expected value we got:




And as we can see
is an unbiased estimator for 
In order to find the variance for the estimator
we have this:

And we can assume that
since the observations are assumed independent, then we have this:

And if we simplify we got:

And with this we complete the proof required.
<u>ANSWER: </u>
The slope of the given line y - 3 = (x - 5) is 1 and (5, 3) is a point on that line.
<u>SOLUTION:
</u>
Given, line equation is y – 3 = (x – 5)
We have to find the slope of the given equation along with a point on that line.
Now, if we observe, the given equation is in point slope form 
Where, m is the slope of the line and
is a point on the line.
Now by comparison of the two equations we can conclude that,

So, the point on the given line is (5, 3).
Hence, the slope of the given line is 1 and (5, 3) is a point on that line.
Answer:
x = 73°
Step-by-step explanation:
a whole circle = 360°
so x + 50° + 91° + 2x = 360°
x+ 2x = 360°- 91° - 50°
3x = 219°
x = 219° ÷ 3
x = 73°
<h2>HOPE THIS HELP YOU!!! ;))))</h2>