The equation is
<h3>Further explanation
</h3>
This case asking the end result in the form of a slope-intercept.
<u>Step-1: find out the gradient.
</u>
10x + 2y = -2
We isolate the y variable on the left side. Subtract both sides by 10x, we get:
2y = - 10x - 2
Divide both sides by two
y = -5x -1
The slope-intercept form is
, with the coefficient m as a gradient. Therefore, the gradient is m = -5.
If you want a shortcut to find a gradient from the standard form, implement this:
10x + 2y = −2 ⇒ a = 10, b = 2
<u>Step-2:</u> the conditions of the two parallel lines
The gradient of parallel lines is the same
. So
<u>Final step:</u> figure out the equation, in slope-intercept form, of the parallel line to the given line and passes through the point (0, 12)
We use the point-slope form.
Given that
- m = -5
- (x₁, y₁) = (0, 12)
y - 12 = - 5(x - 0)
y - 12 = - 5x
After adding both sides by 12, the results is
<u>Alternative steps
</u>
Substitutes m = -5 and (0, 12) to slope-intercept form
12 = -5(0) + c
Constant c is 12 then arrange the slope-intercept form.
Similar results as above, i.e.
<u>Note:
</u>
![\boxed{Standard \ form: ax + by = c, with \ a > 0}](https://tex.z-dn.net/?f=%5Cboxed%7BStandard%20%5C%20form%3A%20ax%20%2B%20by%20%3D%20c%2C%20with%20%5C%20a%20%3E%200%7D)
![\boxed{Point-slope \ form: y - y_1 = m(x - x_1)}](https://tex.z-dn.net/?f=%5Cboxed%7BPoint-slope%20%5C%20form%3A%20y%20-%20y_1%20%3D%20m%28x%20-%20x_1%29%7D)
![\boxed{Slope-intercept \ form: y = mx + k}](https://tex.z-dn.net/?f=%5Cboxed%7BSlope-intercept%20%5C%20form%3A%20y%20%3D%20mx%20%2B%20k%7D)
<h3>
Learn more
</h3>
- A similar problem brainly.com/question/10704388
- Investigate the relationship between two lines brainly.com/question/3238013
- Write the line equation from the graph brainly.com/question/2564656
Keywords: given line, the equation, slope-intercept form, standard form, point-slope, gradien, parallel, perpendicular, passes, through the point, constant