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Delvig [45]
3 years ago
10

ANSWER ASAP/GIVING HIGH RATING DUE SOON,PLS JUST ANSWER I HAVE AKOT OF WORK DUE IN 10 MINS​

Mathematics
1 answer:
Anna35 [415]3 years ago
8 0
$10 if she deposited every month
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Find the difference. Write your answer as a decimal.<br> $5.5-8.1=$
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Sorry I rlllllyyyyyyy don’t understanddddd
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BRAINLIEST!! If the area of ABC is D, give the expressions that complete the equation for the measure of angle C
kati45 [8]

Answer: m= 1+3

Step-by-step explanation:

Basic math helps.

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3 years ago
Solve the equation a/a^2-9 +3/a-3=1/a+3
MAXImum [283]
Answer is: a= -4
STEP
1
:

1
Simplify —————
a + 3
Equation at the end of step
1
:

a 3 1
(————————+—————)-——— = 0
((a2)-9) (a-3) a+3
STEP
2
:

3
Simplify —————
a - 3
Equation at the end of step
2
:

a 3 1
(————————+———)-——— = 0
((a2)-9) a-3 a+3
STEP
3
:

a
Simplify ——————
a2 - 9
Equation at the end of step
3
:

a 3 1
(————————————————— + —————) - ————— = 0
(a + 3) • (a - 3) a - 3 a + 3

Equation at the end of step
4
:

(4a + 9) 1
————————————————— - ————— = 0
(a + 3) • (a - 3) a + 3
Pull out like factors :

3a + 12 = 3 • (a + 4)

Equation at the end of step
6
:

3 • (a + 4)
————————————————— = 0
(a + 3) • (a - 3)

3•(a+4)
——————————— • (a+3)•(a-3) = 0 • (a+3)•(a-3)
(a+3)•(a-3)

a+4 = 0

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3 years ago
A truck travels 2,400 miles in 60 hours, going the same distance each hour.
expeople1 [14]
2400miles/60hours
40miles/hour
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2 years ago
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The speed of the current in a creek is 5 mph. A person clan kayak 3 mi upstream in the same time that it takes him to kayak 13 m
Brut [27]

Answer:

8

Step-by-step explanation:

0) the basic formula is: L=v*t, where L - distance, v - speed/velocity; t - time;

1) if the person's speed in still water is 'v' and the speed of water is 5 (according to the condition), then the upstream speed is 'v-5' and the downstream speed is 'v+5';

2) according to the condition the upstream time and the downstream time are the same, it means t₁=t₂=t, where t₁=upstream time and t₂=downstream time;

3) according to the items above it is possible to make up the equation of the upstream travel: t(v-5)=3; ⇒ t=3/(v-5);

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\frac{3}{v-5} =\frac{13}{v+5}; \ => \ v=8.

8 0
2 years ago
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