Y = -5x + 1
x = 1 , y = -4
x = 2 , y = -9
x = 3 , y = -14
so the answers are
(1,-4)
(2,-9)
(3,-14)
3. ΔPQR ≅ ΔSRT
3. ASA (Angle - Side - Angle) - we have two triangles where we know two angles and the included side are equal
If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent.
4. PR ≅ SR
4. ΔPQR ≅ ΔSRT - the corresponding sides are congruent.
It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.
Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is
<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)
The cosine of the angle between the vectors can be obtained from the dot product identity,
<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>) ==> cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)
so that
<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)
For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is
<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))
==> <em>W</em> ≈ 5.12 J
(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).
So say we have the number: 54,321
The 5 would be worth 50,000 meaning it's in the ten thousands place.
The 4 would be worth 4,000 meaning it's in the thousands place.
.
The difference between them is a zero, so the ten thousands place is 10 times bigger than the thousands place
.
Hope that helps :)
Step-by-step explanation:
multiply it
x²-3x+3x-9=0
x²-9=0
x²=9
square root both side we get
x=3
