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Verdich [7]
2 years ago
8

F(x)=x3 −4x even odd or neither

Mathematics
2 answers:
elixir [45]2 years ago
5 0

Answer:

The function would be odd

Dennis_Churaev [7]2 years ago
4 0

The answer is neither.

Let's take an odd number and substitute.

  • f(3) = 3³ - 4(3)
  • f(3) = 27 - 12
  • f(3) = 15 (odd)

Now, let's take an even number.

  • f(4) = 4³ - 4(4)
  • f(4) = 64 - 16
  • f(4) = 48 (even)

Since both even and odd numbers are possible, it is neither.

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The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it
brilliants [131]

Answer:

(a) 11.25 and 1.68  

(b) 0.1651

(c) 0.3903

(d) 0.6865

Step-by-step explanation:

We are given that GTC, the Georgetown Telephone Company, reports it can resolve customer problems the same day they are reported in 75% of the cases and suppose the 15 cases reported today are representative of all complaints.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 15

             r = number of success

             p = probability of success which in our question is % of cases in

                  which customer problems are resolved on the same day, i.e.;75%

So, here X ~ Binom(n=15,p=0.75)

(a) Expected number of problems to be resolved today = E(X)

            E(X) = \mu = n * p = 15 * 0.75 = 11.25

    Standard deviation = \sigma = \sqrt{n*p*(1-p)} = \sqrt{15*0.75*(1-0.75)} = 1.68

(b) Probability that 10 of the problems can be resolved today = P(X = 10)

     P(X = 10) = \binom{15}{10}0.75^{10}(1-0.75)^{15-10}

                    = 3003*0.75^{10} *0.25^{5} = 0.1651

(c) Probability that 10 or 11 of the problems can be resolved today is given by = P(X = 10) + P(X = 11)

    = \binom{15}{10}0.75^{10}(1-0.75)^{15-10}+\binom{15}{11}0.75^{11}(1-0.75)^{15-11}

    = 3003*0.75^{10} *0.25^{5} + 1365*0.75^{11} *0.25^{4} = 0.3903

(d) Probability that more than 10 of the problems can be resolved today is

    given by = P(X > 10)

P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)  

= \binom{15}{11}0.75^{11}(1-0.75)^{15-11}+\binom{15}{12}0.75^{12}(1-0.75)^{15-12} + \binom{15}{13}0.75^{13}(1-0.75)^{15-13}+\binom{15}{14}0.75^{14}(1-0.75)^{15-14} + \binom{15}{15}0.75^{15}(1-0.75)^{15-15}

= 1365*0.75^{11} *0.25^{4} + 455*0.75^{12} *0.25^{3}+105*0.75^{13} *0.25^{2} + 15*0.75^{14} *0.25^{1}+1*0.75^{15} *0.25^{0}

= 0.6865

3 0
3 years ago
It takes a crew 57 hours to install cabinets in one office. How long will it take the crew to install cabinets in 17 offices?
brilliants [131]

Answer:

969 hours

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Marla bought 12 books at a garage sale. Some of them were hardback and the rest were paperback. She paid $0.50 for each paperbac
olga nikolaevna [1]

Answer: The number of books bought were 9 paperbacks and 3 hardbacks

Step-by-step explanation: We shall start by assigning letters to the unknown variables, hence let the hardback be called h, while the paperback shall be called p.

If Marla bought 12 books at the garage sale, that means she bought

h + p  = 12 ------(1)

Then she paid 0.5 dollars for paperback and 0.75 dollars for hardback and the total spent was 6.75 dollars for all of them, then we can express these as follows;

0.5p + 0.75h = 6.75 ------(2)

We now have a pair of simultaneous equations which are

h + p = 12 ------(1)

0.5p + 0.75h = 6.75 ------(2)

From equation (1), make h the subject of the equation,

h = 12- p

Substitute for h into equation (2)

0.5p + 0.75(12 - p) = 6.75

0.5p + 9 - 0.75p = 6.75

0.5p - 0.75p = 6.75 - 9

-0.25p = -2.25

Divide both sides of the equation by -0.25

p = 9

Now, substitute for p into equation (1)

h + p = 12

h + 9 = 12

Subtract 9 from both sides of the equation

h = 3

Therefore Marla bought 9 paperbacks and 3 hardbacks

6 0
3 years ago
Read 2 more answers
How do you work this out
oksian1 [2.3K]

Answer:

Below.

Step-by-step explanation:

To find the number of students in each grade you multiply the marks by the frequency density. The number of students is given by the area under the  rectangles.

So to find the number of students with grade U (< 160)  it is:

120 * 0.2 + 40*0.5

= 24 + 20

= 44.

The number for Grade E

= (200 - 160) * 0.5

= 40 * 0.5

= 20.

The others can be found in the same way.

6 0
3 years ago
For the diagrams, find the following measures. <br> X= <br> DCB= <br> ABC=
Tasya [4]
To set this up you will set the two angles equal to 180° since it is a straight line
This will make the equation x+6x+19=180
Combine like terms. 7x+19=180.
Subtract 19 from both sides. This will make it 7x=161
Divide both sides by 7. That will make it x=23
Next plug in the x to solve for abc. 7(23)+19. This equals 157

X= 23

Hope this helped :)
8 0
3 years ago
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