6:15:21
6:15:21= 2:5:7
<em>(when divided by 3)</em>
2000=1800(1.04)^t,,log(1.11)/log(1.04)=t use the calculator,,,hope it helps :-)
<span>You are to find the maximum amount of baggage that may be loaded aboard the airplane for the cg (center of gravity) to remain within the moment envelope.
In order to solve this, there is a graph that shows the load weight and the load moment of pilot and front passenger, fuel, rear passenger and passenger including the baggage. Using the given data such as pilot and front passenger 250, the load moment is 9 lbs/in, for the rear passenger at 400lbs, the load moment is 28.5 lbs/in, the fuel at 30 gal has a load moment of 2 lbs/in and oil at 8 quarters is 15 lbs. The total weight is 1,350 + 250 + 400 + 15 is 2015 lbs.</span>
I got 3x^2 + 12x + 4. I recommend you verify my answer, so you have to combine like terms in the first expression then add all the expressions.
Answer: 
Step-by-step explanation:
Given
The height of the cylinder is 
The volume of the cylinder is 
The volume of the cylinder is the product of area and height
Insert the values
Thus, the area of the cross-section is
