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frosja888 [35]
4 years ago
8

Find the equation of the line parallel to the graph of 14x-7y=1 that passes through the point at (-2,4)

Mathematics
1 answer:
Alla [95]4 years ago
8 0

Answer:

The equation of the line would be y = 2x + 8

Step-by-step explanation:

In order to find the equation of the line, we first need to find the slope of the original line. We can do that by solving for y.

14x - 7y = 1

-7y = -14x + 1

y = 2x - 1/7

Now that we have a slope of 2, we know the new slope will be the same since parallel lines have the same slope. So we can use it along with the point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 4 = 2(x + 2)

y - 4 = 2x + 4

y = 2x + 8

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“write an inequality to represent the graph.”
zhuklara [117]

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The inequality for the given graph is y>\frac{2}{3}x-1.

Step-by-step explanation:

From the given graph it noticed that the line passing through (0,-1) and (3,1).

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y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The equation of line is

y+1=\frac{1+1}{3-0}(x-0)

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