1 + tan ² Ф=sec²Ф
1+(12/5)²=sec²Ф
169/25=sec² Ф
sec Ф=⁺₋√(169/25)=⁺₋13/5
sec Ф=1/cos Ф ⇒cosФ=1/sec Ф
cos Ф>0 ⇔ sec Ф>0 ⇔ sec Ф=+ 13/5
cos Ф=1/secФ
cos Ф=1 / 13/5=5/13
we can calculate the sin Ф, with this method.
sin²Ф + cos²Ф=1 ⇒ sin Ф=⁺₋√(1-cos² Ф)
sin Ф=⁺₋√[1-(5/13)²]=⁺₋12/13
like cos Ф>0 and tan Ф>0 ⇒ sin Ф>0 ⇒sin Ф=12/13
answer: d.12/13
other method
tan Ф=sin Ф / cos Ф
12/5=sin Ф / 5/13
sin Ф=(12/5)*(5/13)=12/13
answer: d.12/13
It’s not a function
That’s all I know sorry!
Tbh I really don’t know and I hope someone helps you
OK. Then let's solve for ' r '. That means you have to come up with an equation that says r = everything else.
Step #1:
Write the equation you're given: <span>S = L (1 - r)
Let's divide each side by ' L ': S/L = 1 - r
Subtract 1 from each side : S/L - 1 = -r
Multiply each side by -1 : <em> 1 - S/L = r</em>
and there you have it.
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