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KiRa [710]
3 years ago
7

A chemical company makes two brands of antifreeze. The first brand is 45% pure antifreeze, and the second brand is 95% pure anti

freeze. In order to obtain 90 gallons of a mixture that contains 60% pure antifreeze, how many gallons of each brand of antifreeze must be used?
Mathematics
1 answer:
Lesechka [4]3 years ago
5 0

Let x = amount of 45% antifreezeLet y = amount of 70% antifreeze     EQUATION 1:   x + y = 150    (total of 150 gallons mixed)     EQUATION 2:  .45x + .75y = .55(x + y) Simplify and solve the system of equations     Multiply second equation by 100 on both sides to remove the decimals           45x + 75y = 55(x + y)     Combine like terms           45x + 75y = 55x + 55y           45x - 55x + 75y - 55y = 0             -10x + 20y = 0       Now we have the following system of equations:              x  +    y = 150        -10x + 20y =     0     Multiply the first equation by -10 to get opposite coefficients for x;  add the equations to eliminate x           10x + 10y = 1500         -10x + 20y =       0        ------------------------------                    30y = 1500      Solve for y            30y = 1500                y = 50      Since the total mixed gallons is 150, x = 150 - 50 = 100 So we need 100 gallons of the 45% antifreeze and 50 gallons of the 70% antifreeze

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3 years ago
Match each set of numbers with their least common multiple.
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Answer:

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2 years ago
87 POINTS PLZ HELP Aman is adding –17 + 9. He wants to write –17 as the sum of two numbers so that one of the numbers, when adde
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Consider number 17. You know that

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Then for negative numbers you have the same rule (with respect to sign -):

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3 years ago
A shop sells packs of black pens, packs of red pens and packs of green pens.
olchik [2.2K]

Answer:

85 pens  

Step-by-step explanation:

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And, the ratio of sold of black pens, red pens, and green pans is 7:3:4

So, the ratio of pens in a number of pens is

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3 years ago
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STALIN [3.7K]
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2 years ago
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