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I am Lyosha [343]
2 years ago
5

PLEASE HELP I WILL GIVE 100+ POINTS

Mathematics
1 answer:
Setler [38]2 years ago
7 0
<h2>Answer: </h2>

1. <u>Area = b × h</u>

A = 5 × 3

A = 15cm².

2. <u>Area = ½(a + b) × h</u>

A = ½(9 + 15) × 15

A = ½ × 24 × 15

A = 12 × 15

A = 180mm².

3. <u>Area = 2(l × b) + l × b</u>

A = 2(12 × 4) + 6 × 3

A = 2 × 48 + 18

A = 96 + 18

A = 114m².

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The value of 60 is between which pair of consecutive numbers
finlep [7]
The answer would be
<span>59 and 60.</span>
3 0
3 years ago
A coin purse contains d dimes and q quarters.There are 20 coins in the purse and the total value of the coins is $4.25.which sys
mel-nik [20]
25q + 10d = 425
q + d = 20

First thing's first, picture 4 quarters. Do you know how much these 4 quarters are worth? Obviously, you'd answer one dollar, but take the time to think about how exactly you came up with this answer.

"Well, it's simple," you might think, "Multiply 0.25 by 4."

Similar to this train of thought, the first equation is formulated by doing exactly that. 'q' represents an unknown number of quarters, and 'd' an unknown number of dimes. We use 25q and 10d, because, well, we're multiplying their value by the number of coins. They're equivalent to 425 because the 20 unknown coins make $4.25 (I converted it to cents to get rid of the pesky decimals, but if you want to keep it as dollars that works too).

Because the equation states that there are 20 coins in total, we know that we can make the equation 'q + d = 20' since there are 20 quarters and dimes in total.

Let me know if you need any further explanation :)
-T.B.
3 0
3 years ago
Read 2 more answers
Simplify the problem
Natasha2012 [34]
\frac{6}{10x^2} \div  \frac{6}{10x^3-60x^2}  = \frac{6}{10x^2} \cdot  \frac{10x^3-60x^2}{6}  =\frac{1}{10x^2} \cdot  \frac{10x^2(x-6)}{1}  =x-6
5 0
3 years ago
The first term of a geometric sequence is equal to a and the common ratio of the sequence is r.
ololo11 [35]

Answer: (a)  {a, ar, ar², ar³, ar⁴, ar⁵...}, (b)  arⁿ⁻¹

For part (a), the question gives us the first term a, and then asks us to apply the common ratio r six times.

In order for ar = a, the nth term of r will have to equal 0 (this implies that n is an exponent; thus giving us the first term a, as r = 1).

Since we use this method on the first term, we must use it for the next five, in which r gains an additional exponent for every consecutive value (nth term) thereafter.  

Ultimately getting: {a, ar, ar², ar³, ar⁴, ar⁵...}

For part (b), we first have to understand that the sequence does not start at 0, but at 1 for n. In order for ar = a, with n = 1, there needs to be subtraction of -1 within the exponent. So that arⁿ⁻¹

If we check and apply this, we can see that:

{ar¹⁻¹, ar²⁻¹, ar³⁻¹, ar⁴⁻¹, ar⁵⁻¹, ar⁶⁻¹...} = {a, ar, ar², ar³, ar⁴, ar⁵...} = arⁿ⁻¹ = Tn

4 0
3 years ago
Sally is training for a marathon. She goes for a run every Tuesday and
nikdorinn [45]

Speed = distance / time

Tuesday: speed = 2.4km / 18 minutes = 0.13 km per minute

Friday: speed = 1.8 km / 12 minutes = 0.15 km per minute

0.15 is larger than 0.13 so she ran faster on Friday.

3 0
2 years ago
Read 2 more answers
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