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eimsori [14]
3 years ago
9

Find the slope of the following line. Y=1.4x

Mathematics
2 answers:
Maurinko [17]3 years ago
5 0

Answer:

1.4

Step-by-step explanation:

Using slope-intercept form (y=Mx+b, where m is the slope)

we find that the slope is 1.4, as desired.

Lerok [7]3 years ago
4 0
They answer is Donald trump and lil uzi with that Diamond on his forehead lol !
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Can the following be assumed from a diagram? The measures of angles
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It also means that any angle that is not marked could be acute, right, or obtuse. For example, if this diagram appears without further comment
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3 years ago
The distance between Cincinnati, Ohio, and charlotte, North Carolina, is about 336 miles.The distance between Cincinnati and Chi
Misha Larkins [42]
<span>The distance of Cincinnati going to Charlotte, North CA = 336 miles
The distance of Cincinnati going to Chicago Illinois = 247 miles
Now, Let A = Charlotte, B = Cincinnati and C = Chicago. We assigned a variable to each places to make our illustration simple.
Perry, came from Charlotte, she’s going to Chicago via Cincinnati:
A ------------------------------------------------- B = 336 miles
B ------------------------------------------------- C = 247 miles
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4 0
3 years ago
Whats the equation of a line with slope 3/5 that passes through the point (15,8)
Elden [556K]

Answer:

y=3/5x-1

Step-by-step explanation:

The formula you need to find this would be

(y-y1)=m(x-x1)

The y1 is your y point.

The x1 is your x point.

m is your slope.

Start by plugging in your numbers that they provide you.

(y-8)=3/5(x-15)

Now you need to distribute the slope to the terms inside the parenthesis next to it.

3/5(x)=3/5x

3/5(-15)= -9       Now you put those back into the equation.

(y-8)=3/5x-9

At this point you can get rid of the parenthesis around the y-8 since it is basically saying to take the term times 1.

To get y alone we not need to add 8 to both sides.

y-8=3/5x-9

+8          +8

y=3/5x-1

3 0
4 years ago
Find an equation of the tangent line to the hyperbola x2 a2 − y2 b2 = 1 at the point (x0, y0).
nalin [4]

The equation of the tangent line is y = \frac{b^{2} x_{0}x }{a^{2} y_{0} } - \frac{b^{2} x_{0}^{2}  }{a^{2} y_{0} } + y_{0}

To find the tangent to the hyperbola \frac{x^{2} }{a^{2} } - \frac{y^{2} }{b^{2} } at (x₀, y₀), we differentiate the equation implicitly to find the equation of the tangent at (x₀, y₀).

So, \frac{d}{dx} (\frac{x^{2} }{a^{2} } - \frac{y^{2} }{b^{2} }) = \frac{d0}{dx}\\\frac{d}{dx} \frac{x^{2} }{a^{2} } - \frac{d}{dx}\frac{y^{2} }{b^{2} }= 0\\\frac{2x }{a^{2} } - \frac{dy}{dx}\frac{2y }{b^{2} } = 0\\\frac{2x }{a^{2} } = \frac{dy}{dx}\frac{2y }{b^{2} } \\\frac{dy}{dx} = \frac{b^{2}x }{a^{2}y }

So, at (x₀, y₀)

\frac{dy}{dx} = \frac{b^{2} x_{0} }{a^{2} y_{0} }

So, the equation of the tangent line is gotten from the standard equation of a line in point-slope form

So, \frac{y - y_{0} }{x - x_{0} } = \frac{b^{2} x_{0} }{a^{2} y_{0} }  \\y - y_{0} = \frac{b^{2} x_{0} }{a^{2} y_{0} }(x - x_{0}) \\y = \frac{b^{2} x_{0} }{a^{2} y_{0} }(x - x_{0}) + y_{0} \\y = \frac{b^{2} x_{0}x }{a^{2} y_{0} } - \frac{b^{2} x_{0}^{2}  }{a^{2} y_{0} } + y_{0}

So, the equation of the tangent line is y = \frac{b^{2} x_{0}x }{a^{2} y_{0} } - \frac{b^{2} x_{0}^{2}  }{a^{2} y_{0} } + y_{0}

Learn more about equation of tangent line here:

brainly.com/question/12561220

3 0
3 years ago
Suppose a hypothesis test for a population mean is correctly conducted and the decision is made to not reject the null hypothesi
ArbitrLikvidat [17]

Answer: B) type II error

Step-by-step explanation: whenever hypothesis test is performed it is not possible to be 100% certain about the conclusion or decision made, hence their must be a level of confidence for the conclusion made.

The level of significance (α) usually takes the lower percentage of the area of distribution.

When you reject the null hypothesis instead of accepting it, you commit a type I error, the probability of committing this error is the level of significance (α).

When you accept the null hypothesis when you are suppose to reject it, you commit a type II error and the probability of committing this error is confidence level (β) which is (1- α)

3 0
3 years ago
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