Answer:
I hope it will help you :)
We know that
[area of a regular hexagon]=6*[area of one <span>equilateral triangle]
</span>210.44=6*[area of one equilateral triangle]
[area of one equilateral triangle]=210.44/6-----> 35.07 cm²
[area of one equilateral triangle]=b*h/2
h=7.794 cm
b=2*area/h------> b=2*35.07/7.794------>b= 9 cm
the length side of a regular hexagon is 9 cm
<span>applying the Pythagorean theorem
</span>r²=h²+(b/2)²------>r²=7.794²+(4.5)²------> r²=81--------> r=9 cm
<span>this last step was not necessary because the radius is equal to the hexagon side------> (remember the equilateral triangles)
</span>
the answer is
the radius is 9 cm
Add the similar variables (think apple+apple), in this case, we would add 2q+4q.
Well, what is 4 apples plus 2 apples? 6 apples, simply, 6q
Since 3 is without a variable, we will leave it as is
Therefore, 2q+4q+3= 6q+3
Hope this helped :)
Answer:2x-5
Step-by-step explanation:
