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3 years ago

11

A rectangular prism is 4 inches long, 3 inches wide and 8 inches tall . Eli packs the prism with unit cubes to find the volume.

Abby uses a formula to find the volume

1 answer:

bulgar [2K]3 years ago

6 0

Answer:

$V=96\ inch^2$

Step-by-step explanation:

Given that,

A rectangular prism is 4 inches long, 3 inches wide and 8 inches tall.

We need to find the volume of the rectangular prism. The formula for the volume of prism is given by :

$V=lbh\\\\V=4\times 3\times 8\\\\V=96\ inch^2$

So, the volume of the prism is equal to $96\ inch^2$ .

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It takes four steps to factor 48 – 3y 4 completely. Using complete sentences and the appropriate vocabulary, explain each of the

Nezavi [6.7K]

Answer:

3(2 - y)(2 + y)(4 + y²)

Step-by-step explanation:

48 - 3y⁴

Take 3 common:

3(16 - y⁴)

16 is 4² and y⁴ is (y²)²

3(4² - (y²)²)

Using a² - b² = (a - b)(a + b)

3(4 - y²)(4 + y²)

Again, 4 = 2²

3(2² - y²)(4 + y²)

3(2 - y)(2 + y)(4 + y²)

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3 years ago

I need help to solve this multi step equation please give me the correct answer

kozerog [31]

Answer:

291 - 5y

Step-by-step explanation:

x- a measure of the fourth angle

The equation

$x+60+(2y+8)+(3y+1)=360\qquad|\text{combine like terms}\\\\x+(2y+3y)+(60+8+1)=360\\\\x+5y+69=360\qquad|\text{subtract 5y and 69 from both sides}\\\\x=291-5y$

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4 years ago

The value of polynomial 5x-4x^2+3, when x=-1<br>

Alchen [17]

Answer:

-6

Step-by-step explanation:

$\text{Given that,}\\\\5x-4x^2 +3 \\\\\text{When}~ x = -1,\\\\~~~5(-1) -4(-1)^2 +3 \\\\=-5-4(1)+3\\\\=-5-4+3\\\\=-5-1\\\\=-6$

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2 years ago

Explain what the Diameter is and how is the radius related to it.

horrorfan [7]

Answer:

The diameter is any straight line that passes through the center of the circle, which endpoints can lie on. The radius is half the diameter. They help us find the circumference of a circle

6 0

3 years ago

Read 2 more answers

Initially a tank contains 10 liters of pure water. Brine of unknown (but constant) concentration of salt is flowing in at 1 lite

zhenek [66]

Answer:

Therefore the concentration of salt in the incoming brine is 1.73 g/L.

Step-by-step explanation:

Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.

Let the concentration of salt be a gram/L

Let the amount salt in the tank at any time t be Q(t).

$\frac{dQ}{dt} =\textrm {incoming rate - outgoing rate}$

Incoming rate = (a g/L)×(1 L/min)

=a g/min

The concentration of salt in the tank at any time t is = $\frac{Q(t)}{10}$ g/L

Outgoing rate = $(\frac{Q(t)}{10} g/L)(1 L/ min)$ $\frac{Q(t)}{10} g/min$

$\frac{dQ}{dt} = a- \frac{Q(t)}{10}$

$\Rightarrow \frac{dQ}{10a-Q(t)} =\frac{1}{10} dt$

Integrating both sides

$\Rightarrow \int \frac{dQ}{10a-Q(t)} =\int\frac{1}{10} dt$

$\Rightarrow -log|10a-Q(t)|=\frac{1}{10} t +c$ [ where c arbitrary constant]

Initial condition when t= 20 , Q(t)= 15 gram

$\Rightarrow -log|10a-15|=\frac{1}{10}\times 20 +c$

$\Rightarrow -log|10a-15|-2=c$

Therefore ,

$-log|10a-Q(t)|=\frac{1}{10} t -log|10a-15|-2$ .......(1)

In the starting time t=0 and Q(t)=0

Putting t=0 and Q(t)=0 in equation (1) we get

$- log|10a|= -log|10a-15| -2$

$\Rightarrow- log|10a|+log|10a-15|= -2$

$\Rightarrow log|\frac{10a-15}{10a}|= -2$

$\Rightarrow |\frac{10a-15}{10a}|=e ^{-2}$

$\Rightarrow 1-\frac{15}{10a} =e^{-2}$

$\Rightarrow \frac{15}{10a} =1-e^{-2}$

$\Rightarrow \frac{3}{2a} =1-e^{-2}$

$\Rightarrow2a= \frac{3}{1-e^{-2}}$

$\Rightarrow a = 1.73$

Therefore the concentration of salt in the incoming brine is 1.73 g/L

8 0

3 years ago