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Blababa [14]
3 years ago
10

A magazine provided results from a poll of 1000 adults who were asked to identify their favorite pie. Among the 1000 ​respondent

s, 14 ​% chose chocolate​ pie, and the margin of error was given as plus or minus 3 percentage points. What values do ModifyingAbove p with caret ​, ModifyingAbove q with caret ​, ​n, E, and p​ represent? If the confidence level is 95 ​%, what is the value of alpha ​?
Mathematics
1 answer:
Novay_Z [31]3 years ago
8 0

Answer:

The value of <em>α</em> is 0.05.

Step-by-step explanation:

A poll of 1000 adults was conducted to determine their favorite pie.

The poll result states that among the 1000 ​respondents, 14 ​% chose chocolate​ pie, and the margin of error was given as plus or minus 3 percentage points.

\hat p=\text{Sample Proportion of adults who chose chocolate pie} = 0.14\\\hat q=\text{Sample Proportion of adults who did not chose chocolate pie}\\=1-\hat p\\=0.86\\n=\text{Sample size}=1000\\E=\text{Margin of Error}=0.03\\p=\text{Population Proportion of adults who chose chocolate pie}

The confidence level is 95%.

Determine the value of significance level, <em>α</em> as follows:

\text{Confidence Level}=(1-\alpha)\%\\\\95\%=(1-\alpha)\%\\\\0.95=(1-\alpha)\\\\\alpha=1-0.95\\\\\alpha=0.05

Thus, the value of <em>α</em> is 0.05.

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​f(x)=5​x reflected over the x axis
postnew [5]

Answer:

f(x) = -5x

Step-by-step explanation:

Just add a - sign to reflect it over the x axis

6 0
3 years ago
Find the point(s) on the surface z^2 = xy 1 which are closest to the point (7, 11, 0)
leonid [27]
Let P=(x,y,z) be an arbitrary point on the surface. The distance between P and the given point (7,11,0) is given by the function

d(x,y,z)=\sqrt{(x-7)^2+(y-11)^2+z^2}

Note that f(x) and f(x)^2 attain their extrema, if they have any, at the same values of x. This allows us to consider the modified distance function,

d^*(x,y,z)=(x-7)^2+(y-11)^2+z^2

So now you're minimizing d^*(x,y,z) subject to the constraint z^2=xy. This is a perfect candidate for applying the method of Lagrange multipliers.

The Lagrangian in this case would be

\mathcal L(x,y,z,\lambda)=d^*(x,y,z)+\lambda(z^2-xy)

which has partial derivatives

\begin{cases}\dfrac{\mathrm d\mathcal L}{\mathrm dx}=2(x-7)-\lambda y\\\\\dfrac{\mathrm d\mathcal L}{\mathrm dy}=2(y-11)-\lambda x\\\\\dfrac{\mathrm d\mathcal L}{\mathrm dz}=2z+2\lambda z\\\\\dfrac{\mathrm d\mathcal L}{\mathrm d\lambda}=z^2-xy\end{cases}

Setting all four equation equal to 0, you find from the third equation that either z=0 or \lambda=-1. In the first case, you arrive at a possible critical point of (0,0,0). In the second, plugging \lambda=-1 into the first two equations gives

\begin{cases}2(x-7)+y=0\\2(y-11)+x=0\end{cases}\implies\begin{cases}2x+y=14\\x+2y=22\end{cases}\implies x=2,y=10

and plugging these into the last equation gives

z^2=20\implies z=\pm\sqrt{20}=\pm2\sqrt5

So you have three potential points to check: (0,0,0), (2,10,2\sqrt5), and (2,10,-2\sqrt5). Evaluating either distance function (I use d^*), you find that

d^*(0,0,0)=170
d^*(2,10,2\sqrt5)=46
d^*(2,10,-2\sqrt5)=46

So the two points on the surface z^2=xy closest to the point (7,11,0) are (2,10,\pm2\sqrt5).
5 0
3 years ago
Please help immediately
frutty [35]
The answer is D

Hope this helped
4 0
3 years ago
Read 2 more answers
The image shows the distances in miles between three cities. How much closer is it to travel from Aurora to Clifton directly tha
murzikaleks [220]

Answer:

First we need to calculate the distance between Clifton and Burlington by using Pythagorean theorem:

    x² + 65² = 97²

=> x²           = 97² - 65²

=> x²           = 5184

=> x             = √5184 = 72 (m)

The total distance from Aurora to Clifton through Burlington is: 65 + 72 = 137 (m)

We have: 137 - 97 = 40 (m)

So it is 40 m  closer to travel from Aurora to Clifton directly than from Aurora to Clifton through Burlington

7 0
3 years ago
The system of equations y=4x y-4=4 (x-1) has.
Alekssandra [29.7K]

Answer:

infinitely many solutions.

Step-by-step explanation:

y=4x

y-4=4 (x-1)

Lets substitute the first equation into the second equation.

4x -4 = 4(x-1)

Distribute

4x-4 = 4x-4

Subtract 4x from each side

4x-4x-4 =4x-4x-4

-4=-4

This is always true.  X can be anything.  We have infinite solutions

6 0
3 years ago
Read 2 more answers
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