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3 years ago

10

I have a classroom where I answer algebra questions. Here is the link and I'll try to answer your question. Let me know if you c

an't access it.
It's not letting me post the link so ill try to put it in the comments.

2 answers:

poizon [28]3 years ago

7 0

I will try thanks for letting me know

USPshnik [31]3 years ago

6 0

Answer:

Okay thanks

Step-by-step explanation:

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Colin’s average for three rounds of golf is 94. What is the highest score he can receive for the fourth round to have an average

Lostsunrise [7]

Answer:86

Step-by-step explanation: The lowest score that he could get in the fourth round is 86 in order to have an average of 92. The steps that you would take to calculate this are as follows:

Multiply 92 x 4 = equals the total number of points that he needs to earn in all four rounds

92 x 4 = 368

Next, subtract the total for the first three rounds. Since the average is 94, you will subtract the total of 3 x 94, which equals 282.

Subtract 368 - 282 = 86.

You can then double check your work by adding up the total of the four games and dividing by four for the average. 94+94+94+86=368 368/4=92

4 0

4 years ago

Triangle FGH has the following side lengths: FG = 5 ft, GH = 10 ft, HF = 12 ft Triangle PQR is similar to triangle FGH. The long

7nadin3 [17]

The first thing we must do for this case is find the scale factor.
We have then that for the larger side of both triangle, the scale factor is:
$k = \frac{RP}{HF}$
$k = \frac{7.2}{12}$
$k = 0.6$
To find the other two sides, we must apply the scale factor on each side of the triangle FGH.
We have then:

For PQ
$PQ = k * FG

PQ = 0.6 * 5

PQ = 3$

For QR
$QR = k * GH

QR = 0.6 * 10

QR = 6$

Answer:
You have that the lengths for the other two sides of triangle PQR are:
$PQ = 3

QR = 6$

3 0

4 years ago

8/9+4/7<img src="https://tex.z-dn.net/?f=8%2F9%20%2B4%2F7" id="TexFormula1" title="8/9 +4/7" alt="8/9 +4/7" align="absmiddle" cl

uysha [10]

2-9/9 ion kno what this is sorry

3 0

3 years ago

the name Joe is very common at a school in one out of every ten students go by the name. If there are 15 students in one class,

kumpel [21]

Using the binomial distribution, it is found that there is a 0.7941 = 79.41% probability that at least one of them is named Joe.

For each student, there are only two possible outcomes, either they are named Joe, or they are not. The probability of a student being named Joe is independent of any other student, hence, the <em>binomial distribution</em> is used to solve this question.

<h3>Binomial probability distribution </h3>

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

One in ten students are named Joe, hence $p = \frac{1}{10} = 0.1$ .

There are 15 students in the class, hence $n = 15$ .

The probability that at least one of them is named Joe is:

$P(X \geq 1) = 1 - P(X = 0)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{15,0}.(0.1)^{0}.(0.9)^{15} = 0.2059$

Then:

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2059 = 0.7941$

0.7941 = 79.41% probability that at least one of them is named Joe.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

8 0

3 years ago

How do you know if a graph is not proportional?

amid [387]

When it is not straight

6 0

3 years ago

Read 2 more answers