Answer:
Z = (60 - x + y + z) / √a + b + c
Step-by-step explanation:
Since it is a normal distribution, we must calculate the mean and standard deviation, since we do not have data, what we will do is leave them based on these:
Thus Total Mean time = M1 + M2 + M3
given:
M1 = x
M2 = y
M3 = z
Total Mean Time M = x + y + z
Now to calculate the standard deviation we first calculate the variance.
The total Variance V = V1 + V2 + V3
Given:
V1 = a
V2 = b
V3 = c
V = a + b + c
Thus Standard deviation SD of the complete operation is
SD = √ V
SD = √a + b + c
we need to find the probability that the mean time is less than or equal to 60 minutes, the first thing is to find the value of Z.
Formula of Z is:
Z = (X - M) / SD
In this case X = 60.
On plugging the values we get
Z = (60 - x + y + z) / √a + b + c
refer to the Z table and find the Probability of Z ≤ (60 - x + y + z) / √a + b + c
Consider the universal set U and the sets X, Y, Z. U={1,2,3,4,5,6} X={1,4,5} Y={1,2} Z={2,3,5} What is (Z⋃X′)⋂Y?
beks73 [17]
X' = U - X
= {1,2,3,4,5,6} - {1,4,5}
= {2,3,6}
(ZUX') = {2,3,5} U {2,3,6}
= {2,3,5,6}
(Z⋃X′)⋂Y = {2,3,5,6} ⋂ {1,2}
= {2}
Y =

x + 3
y = x - 4
Since both equations are equal to y, you can set the two values equal to each other and solve for x.

x + 3 = x - 4 Multiply both sides by 2
x + 6 = 2x - 8 Add x to both sides
6 = 3x - 8 Add 8 to both sides
14 = 3x DIvide both sides by 3
4
= x
Now, plug the x value into one of the original equations, I'll plug it into y = x - 4.
y = x - 4 Plug in the x value
y = 4

- 4 Subtract
y =
x = 4
and
y =
Answer:
Step-by-step explanation:
Answer:
14
Step-by-step explanation: