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jarptica [38.1K]
3 years ago
9

Find the inverse of the function y = cube root (x/3)-1

Mathematics
1 answer:
lianna [129]3 years ago
4 0
Hello here is a solution : 

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Will mark brainliest if correct! :)
fgiga [73]

Answer:

The volume of cone = 1/3 vol of cylinder = 1/3 406.8 = 406.8/3 = 195.6

7 0
3 years ago
Suppose your heart beats 70 times a minute. How long would it take for it to beat 1 million times?
Nina [5.8K]

Answer:

14285.7142857

Step-by-step explanation:

1 mil divided by 70= 14285.7142857

6 0
3 years ago
Having trouble with this math problem. I really would like some help
Pavlova-9 [17]
The answer would have to be C because he cannot sell negative hats or infinitely many because he only has 300 to sell in the first place. Answer choice D makes no sense because there is no value of x that is less than zero and greater than 500.
5 0
4 years ago
Read 2 more answers
How do i solve <br> −4(m+6)=−8
geniusboy [140]

Answer: -4 (m + 6) = -8

We can use the distributive property for the first half of the equation.

-4 × m = -4m    

-4 × 6 = -24

-4m - 24 = -8

Now we add 24 on bothe side sof the equation to get -4m by itself.

-4m - 24 + 24 = -8 + 24

Now we get -4m = 16

Divide -4 on both sides to get m by itself

-4m/-4 = 16/-4 

Simplify and we get m = -4

4 0
3 years ago
Read 2 more answers
Help help help pls pls pls
alex41 [277]

Answer: 14.48000 . . . ≤ t < 15.0000

Step-by-step explanation:

"Truncated by a hundreths of a second" means that the time was rounded to the nearest 0.0X second.  That would mean the reported time of 14.48 seconds was shortened from a time period having more digits to the right.  For example, If the time were actually 14.48223 seconds, the time was truncated to just 14.48 seconds.  The term used here. truncated, means that the digits after the hunredth place are simply dropped.  It doesn't say rounded, just truncated.  Brutal.  So that would mean that times between 14.48000 . . . and 14.48999 . . . would all be reported as 14.48 seconds.

So the time could actually be 14.48000 . . . ≤ t < 15.0000

3 0
3 years ago
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