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Gelneren [198K]
3 years ago
13

22. Using the graph, state the approximate

Mathematics
2 answers:
KonstantinChe [14]3 years ago
6 0

Answer:

I believe Awnser B..  (0.5, 0)

Step-by-step explanation:

Inga [223]3 years ago
3 0
The answer is B, because if you look at the graph it’s in between 0 and 1, and the number in between them is 0.5. Also it doesn’t move down or up so it would also be 0.

Answer: So the answer is (0.5, 0).

Hope this helps!!
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600 students were going on a field trip.
laiz [17]

Answer:

6,000 total items

Step-by-step explanation:

3*600=1800   (total juice)

2*600=1200   (total fruit)

2*600=1200   (total burritos)

2*600=1200   (total doritos)

1*600=600     (total milk)

1800+1200+1200+1200+600=6000

3 0
3 years ago
Sandy charges each family that she babysits a flat fee of 10$ for the night and an extra 5$ per child kimmi charges 25$ per nigh
Rudiy27
Sandy's cost equation is y = 5x + 10 where y = cost and x = number of children.
Kimmi's cost equation is y = 25 where y = cost.
The fees are the same when x = 3 in other words when Sandy babysits 3 children.
That is found by solving 5x + 10 = 25 for x.
Subtract 10 from each side: 5x = 15
Divide by 5 on both sides: x = 3
5 0
3 years ago
3/4x8/9 as simpiest form
anyanavicka [17]

Answer:

2/3

Step-by-step explanation:

3/4 x 8/9 = 24/36 or 2/3 simplified

3 0
3 years ago
If f(x) and its inverse function, fx), are both plotted on the same coordinate plane, what is their point of intersection?
Lubov Fominskaja [6]

Answer: (3, 3)

Step-by-step explanation:

the graphs of f and f^{-1 are flipped: if the point (x, y) is on the graph of f, then the point (y, x) is on the graph of f^{-1.

Any points of intersection will satisfy (x, y) = (y, x). A point that satisfies this property must have the same x and y coordinate. (Think about it.) The only point on f like that is (3, 3), so that is the point of intersection.

7 0
2 years ago
Which of the following is not the graph of a function of x?​
Paraphin [41]

Answer:

i think it's the third one

6 0
3 years ago
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