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3 years ago

BRANIEST !!!!!!!! PLEASE HELP!!!!

Mathematics

2 answers:

Trava [24]3 years ago

3 0

Answer:

B. y= x^2 + 1

Step-by-step explanation:

I graphed it

alexgriva [62]3 years ago

3 0

Answer:

.........B..........

Step-by-step explanation:

i think it is because (X+1)^2 means X^2+1

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Find the limit

Lana71 [14]

Step-by-step explanation:

<h3>Appropriate Question :-</h3>

Find the limit

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

On substituting directly x = 1, we get,

$\rm \: = \: \sf \dfrac{1-2}{1 - 1}-\dfrac{1}{1 - 3 + 2}$

$\rm \: = \sf \: \: - \infty \: - \: \infty$

which is indeterminant form.

Consider again,

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

can be rewritten as

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 3x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 2x - x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( x(x - 2) - 1(x - 2))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ {(x - 2)}^{2} - 1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 2 - 1)(x - 2 + 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)(x - 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)}{x(x - 2)}\right]$

$\rm \: = \: \sf \: \dfrac{1 - 3}{1 \times (1 - 2)}$

$\rm \: = \: \sf \: \dfrac{ - 2}{ - 1}$

$\rm \: = \: \sf \boxed{2}$

Hence,

$\rm\implies \:\boxed{ \rm{ \:\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right] = 2 \: }}$

$\rule{190pt}{2pt}$

7 0

3 years ago

Read 2 more answers

in a school ,the number of boys who play cricket is 3 times as much as a number of boys who play tennis. if 12 boys, who play cr

Ierofanga [76]

Answer:

The number of boys who play tennis is 36.

Step-by-step explanation:

Let the number of boys who play tennis is x.

number of boys who play cricket = y

x = 3 y..... (1)

12 boys plays both cricket and tennis.

According to the question,

x - 12 = y + 1 2

3 y - 12 = y + 12

2 y = 24

y = 12

So, the number of boys who plays tennis is x = 3 x 12 = 36.

8 0

3 years ago

Maddy has a bag of 36 marbles. The probability of picking green is 1 in 2, the probability of picking red is 1 in 3, and the pro

KonstantinChe [14]

Answer: 1 in 18

This is the same as writing the fraction 1/18

==============================================================

Explanation:

Since she has 36 marbles total, and the probability of picking green is 1 in 2, this means (1/2)*36 = 18 marbles are green.

Then she also has (1/3)*36 = 12 red marbles and (1/9)*36 = 4 blue marbles.

So far, that accounts for 18+12+4 = 34 marbles in all. That leaves 36-4 = 2 marbles left over that must be black, as it's the only color left.

From that, the probability of choosing a black marble is 2/36 = 1/18.

There's a 1 in 18 chance of Maddy picking a black marble.

1/18 = 0.0556 = 5.56% approximately

7 0

3 years ago

Least to greatest 87% 0.432 2/8

Scorpion4ik [409]

Answer: 2/8, 0.432, 87%

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Mrs. White's students are making school spirit packs. They have 24 bumper stickers and 18 window clings. Every pack must have th

ExtremeBDS [4]

Answer:

6 packet.

Step-by-step explanation:

Given:

Mrs. White's students are making school spirit packs.

They have 24 bumper stickers and 18 window clings.

Every pack must have the same contents and there should be no leftover items.

Question asked:

What is the greatest number of packs they can make?

Solution:

To find the greatest number of packs could be made by 24 bumper stickers and 18 window clings by using same contents in each pack with no left over items, we will simply use Highest Common Factor.

Factor of 24 - 2, 3, 4, 6, 8, 12, 24

Factor of 18 - 2, 3, 6, 9, 18

Highest Common Factor is 6.

Thus, they can make 6 packet at most.

3 0

3 years ago