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3 years ago

BRANIEST !!!!!!!! PLEASE HELP!!!!

Mathematics

2 answers:

Trava [24]3 years ago

3 0

Answer:

B. y= x^2 + 1

Step-by-step explanation:

I graphed it

alexgriva [62]3 years ago

3 0

Answer:

.........B..........

Step-by-step explanation:

i think it is because (X+1)^2 means X^2+1

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Find the sale price to the nearest cent. $4.30 makeup; 40% discount; 6% tax

katrin [286]

Answer:

Sale price is $2.58.

Paid with tax is $2.73

Step-by-step explanation:

If the make-up is originally $4.30 and you receive a 40% discount. This means you'll pay 60% of the price since 100-40=60.

To find this price, 60% as 0.6 is multplied with the price. 0.6*4.30 = $2.58

This is the sale price.

When you pay you will pay 6% tax or 0.06 of the price. Find this by multiplying $2.58 by 1.06.

2.58(1.06) = $2.73

7 0

3 years ago

25% of 1 min (in sec)

MAVERICK [17]

Answer : 15 seconds

25% is equal to 1/4, so you can just divide 60 seconds by 4, and that gives you the answer.

7 0

3 years ago

Read 2 more answers

A monomial usually has the form ______, where a is ______ and n is a ______?

Ksenya-84 [330]

a monomial usually has the form _ax_^n____, where a is __constant____ and n is a __integer____?

5 0

4 years ago

Tim has an after-school delivery service that he provides for several small retailers in town. He uses his bicycle and charges $

nlexa [21]

Answer:

$4.84

Step-by-step explanation:

Given that

For delivery within $1\frac{1}2$ mi, charges = $1.25

For delivery within $1\frac{1}2$ mi - $1\frac{3}4$ mi, charges = $1.70

For delivery within $1\frac{3}4$ mi - 2 mi, charges = $2.15

and

so on.

i.e.

For delivery within 2 mi - 2 $\frac{1}4$ mi, charges = $2.60

For delivery within 2 $\frac{1}4$ mi - 2 $\frac{1}2$ mi, charges = $3.05

For delivery within 2 $\frac{1}2$ mi - 2 $\frac{3}4$ mi, charges = $3.50

For delivery within 2 $\frac{3}4$ mi - 3 mi, charges = $3.95

For delivery within 3 mi - 3 $\frac{1}4$ mi, charges = $4.40

So, every 0.25 mi or $\frac{1}4$ mi increase in distance, there is an increase of $0.45 in the charges.

It is given that there is increase of 10% in the rates.

i.e. for every 0.25 mi increase in distance, there is an increase of 0.45*1.10 = $0.495 in the charges.

The distance of $3\frac{1}8$ miles lies within the range 3 mi - 3 $\frac{1}4$ mi.

So actual charges after increase of 10%

$\Rightarrow \$4.40 \times \dfrac{110}{100}\\\Rightarrow \$4.40 \times 1.10\\\Rightarrow \bold{\$4.84}$

6 0

4 years ago

WHAT IS .115 IN EXPANDED FORM

ivolga24 [154]

0.115 = 0.1 + 0.01 + 0.005

hope it helps

7 0

3 years ago