Answer:
Translation 9 units to the left, and 2 units up
Step-by-step explanation:
Answer:
Step-by-step explanation:
Key features
when t = 0
the initial height is 143/3 = 47⅔ ft
initial velocity is -310/3 = -103⅓ ft/s (downward)
initial acceleration is 2(64) = 128 ft/s² (upward)
I would not like to ride this roller coaster!
that's about four times the acceleration of gravity, and it only increases as the car gets to the bottom of the curve at t = 1 s
For part 3
I'm not sure what they mean by "not realistic"
while the initial acceleration is high. the acceleration at t = 1 is zero except that in 'reality' the car would have to be going through a curve to change direction from down to up. That would create very high centripetal acceleration and therefore centripetal forces.
90in I think is the answer
Answer:
The correct option is O B'
Step-by-step explanation:
We have a quadrilateral with vertices A, B, C and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units away from the line, C is 7 units away from the line and D is 9 units away from the line.
Now we perform the reflection and we obtain a new quadrilateral A'B'C'D'.
In order to apply the reflection to the original quadrilateral ABCD, we perform the reflection to all of its points, particularly to its vertices.
Wherever we have a point X and a line of reflection L and we perform the reflection, the new point X' will keep its original distance from the line of reflection (this is an important concept in order to understand the exercise).
I will attach a drawing with an example.
Finally, we only have to look at the vertices and its original distances to answer the question.
The vertice that is closest to the line of reflection is B (the distance is 4 units). We answer O B'