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exis [7]
3 years ago
15

A tennis ball is in a cylindrical container. The ball has a radius of 5 inches and the cylinder has a height of 8 inches. How mu

ch wasted space (air) is there in the container? The tennis ball touched the sides, top, and bottom of the container.) Give your answer in terms of pi. *
Mathematics
1 answer:
Nostrana [21]3 years ago
7 0

Answer:

104.7 in^3

Step-by-step explanation:

Step one:

given data

The ball has a radius of 5 inches and

the cylinder has a height of 8 inches

Step two:

The volume of the cylinder

v= \pi r^2 h

substitute our data

v= 3.142*5^2*8\\\\v=628.4in^3

The volume of the ball

v=4/3 \pi r^3

substitute our data

v= 4/3 *3.142*5^3\\\\v= 523.7 in^3

The space will have a volume of

=628.4-523.7

=104.7 in^3

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Tue 05/28<br> 11. Find the common ratio of the sequence.<br> 2, -10,50.-250,<br> 0-5<br> .
Montano1993 [528]

Answer:

-5

Step-by-step explanation:

Geometric sequences have common ratios.

You can see if a sequence is geometric by computing:

\frac{\text{term}}{\text{previous term}}.

If you get the same result per consecutive pair, then there is a common ratio and the sequence is geometric.

Let's see:

\frac{-250}{50}=\frac{50}{-10}=\frac{-10}{2}

So if this equations holds (if all 3 fractions equal the same thing), then is geometric and we have also have computed the common ratio.

The first fraction results in -250/50=-5.

The second fraction results in 50/-10=-5.

The third fraction results in -10/2=-5.

All three fractions are equal and so the equation holds so it is geometric and the common ratio is -5.

5 0
3 years ago
The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the v
Svetllana [295]

Answer:

The differential equation becomes -

\frac{dV}{dt} = k\sqrt[3]{V} i.e. \frac{dV}{dt} = kV^{\frac{1}{3} }

Step-by-step explanation:

Given - The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the volume.

To find - Write a differential equation that describes the relationship.

Proof -

Rate of change of volume V with respect to time t is represented by \frac{dV}{dt}

Now,

Given that,

The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the volume.

⇒\frac{dV}{dt} ∝ \sqrt[3]{V}

Now,

We know that, when we have to remove the Proportionality sign , we just put a constant sign.

Let k be any constant.

So,

The differential equation becomes -

\frac{dV}{dt} = k\sqrt[3]{V} i.e. \frac{dV}{dt} = kV^{\frac{1}{3} }

6 0
3 years ago
PLEASE HELP HELP!!! PRECALC
brilliants [131]

Answer:

The base is 0.1

The base is less than 1 so the function is decreasing

The x intercept is (3,0)

Step-by-step explanation:

The base of a logarithm refers to the number that must be raised to the power of the number on the right hand side of the logarithmic equation in order to yield the number on the left hand side of the logarithmic equation. It is always written as a subscript below the log symbol. In this case, the base is 0.1.

When the base of a logarithm is less than 1, it means that the function is decreasing as is the case in this question.

Looking at the graph, the x axis is cut at the point (3,0). This is the x-intercept of the graph.

4 0
3 years ago
Which of these could be the remainder of a number divided by 6?<br><br> 4<br> 7<br> 8<br> 9
Stells [14]

Answer:

i have a feeling its 4

Step-by-step explanation:

8 0
3 years ago
What is the location of point A?
AlladinOne [14]

Answer:

C.-1.6

Step-by-step explanation:

distance: -1 - (-2) = 1

1 ÷ 5 = 1/5

-1 - 1/5 × 3 = -1 3/5 = -1.6

3 0
3 years ago
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