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exis [7]
2 years ago
15

A tennis ball is in a cylindrical container. The ball has a radius of 5 inches and the cylinder has a height of 8 inches. How mu

ch wasted space (air) is there in the container? The tennis ball touched the sides, top, and bottom of the container.) Give your answer in terms of pi. *
Mathematics
1 answer:
Nostrana [21]2 years ago
7 0

Answer:

104.7 in^3

Step-by-step explanation:

Step one:

given data

The ball has a radius of 5 inches and

the cylinder has a height of 8 inches

Step two:

The volume of the cylinder

v= \pi r^2 h

substitute our data

v= 3.142*5^2*8\\\\v=628.4in^3

The volume of the ball

v=4/3 \pi r^3

substitute our data

v= 4/3 *3.142*5^3\\\\v= 523.7 in^3

The space will have a volume of

=628.4-523.7

=104.7 in^3

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Step-by-step explanation:

From the question

Jesse has $3.40 in quarters and nickels

Quarters = q = number of quarters

1 quarter = $0.25

nickels = n = number of nickels

1 nickel = $0.05

Hence,

0.25q + 0.05n = $3.40 .......Equation 1

The number of nickels is 5 more than 2 times the number of quarters.

n = 2q + 5

0.25q + 0.05n = $3.40 .......Equation 1

0.25q + 0.05(2q + 5) = 3.40

0.25q + 0.10q + 0.25= 3.40

0.35q = 3.40 - 0.25

0.35q = 3.15

q = 3.15/0.35

q = 9

Therefore, Jessie has 9 quarters.

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