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exis [7]
2 years ago
15

A tennis ball is in a cylindrical container. The ball has a radius of 5 inches and the cylinder has a height of 8 inches. How mu

ch wasted space (air) is there in the container? The tennis ball touched the sides, top, and bottom of the container.) Give your answer in terms of pi. *
Mathematics
1 answer:
Nostrana [21]2 years ago
7 0

Answer:

104.7 in^3

Step-by-step explanation:

Step one:

given data

The ball has a radius of 5 inches and

the cylinder has a height of 8 inches

Step two:

The volume of the cylinder

v= \pi r^2 h

substitute our data

v= 3.142*5^2*8\\\\v=628.4in^3

The volume of the ball

v=4/3 \pi r^3

substitute our data

v= 4/3 *3.142*5^3\\\\v= 523.7 in^3

The space will have a volume of

=628.4-523.7

=104.7 in^3

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Kara works at a fine jewelry store and earns commission on her total sales for the week. Her weekly paycheck was in the week tot
GrogVix [38]

Answer:

12.2%

Step-by-step explanation:

Her total paycheck minus her salary = the commission amount

So

6500 - 1000 = 5500

So....her commission as a percentage of sales  = 5500/ 45000 = about 12.2%

3 0
3 years ago
A bicycle store installs about 400 tires per day. Tires are installed Monday through Friday for 8 hours per day. The owner of th
dalvyx [7]
Dividing the number of tires that should be installed per day which  is 400 by the number of working hours which is 8 will give us 50 tires per hour. Assuming that the same mistake will take toll on the workers such that they will have 1 tire mistakenly installed in an hour, they will have 8 erroneous tires in a day. Multiplying this by 5 to make the answer per week will give 40. Out of the 400 x 5  = 2000 tires. The answer would be 2000 - 40 which is equal to 1940. The assumption must be valid. 
6 0
3 years ago
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How to expand and evaluate
Nana76 [90]
(-1.1)*(-1.1)*(-1.1)=-1.331
8 0
3 years ago
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
2 years ago
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Find the area of triangle ABC<br> please help asap!
Daniel [21]

Step-by-step explanation:

The Base of the triangle= 3+6=9 units

Altitude of the triangle=6-2=4 units

Hence, Area of a triangle= Base×Altitude ×1/2

Hence, Area of the abc = 9×4×1/2=18 unit^2

3 0
3 years ago
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