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timama [110]
2 years ago
10

Triangle ABC is given. What is the measure, in degrees, of ∠A?

Mathematics
1 answer:
zheka24 [161]2 years ago
4 0

Answer:

Angle A = 56° check the attachment for detailed solution

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Find the angle measures. Justify your responses. Given: a||b, m1=71º Find m5, m8
Natalka [10]

Answer:

The measure of angle MNP is

m ∠ MNP =  (x - y)/2

Explanation:

The image attached shows the figure corresponding to this question.

The angle MNP, which is also the angle LNP, is formed by the intersection of a secant and a tangent to a circle.

Then, you can use the theorem:

the angle formed by a secant and a tangent to a circle that intersect outside the circle is half the difference of the major arc minus the minor arc.

The major arc formed is identified with the letter x and the minor arc is identified with the letter y. Thus, the measure of the angle MNP is half the difference x - y:

m ∠ MNP = (x - y)/2

Brainliest please

7 0
2 years ago
17. Jing has $800 to deposit into two different savings accounts.
Olin [163]

Answer:

$864.88

Step-by-step explanation:

(1. $600 + $49.50 = $649.50

(2. $200 + $15.38 = $215.38

$649.50 + $215.38 = $864.88

A = $864.88

7 0
3 years ago
Can someone simply explain how to find the area of a triangular prism ? step by step ^^;
Vika [28.1K]
The formula:
A = bh + L (s1 + s2 + s3)

A: area
b: base
h: height
L: length
s1: side 1 (cross-sectional area)
s2: side 2 (cross-sectional area)
s3: side 3 (cross-sectional area)

Here’s an example (see attached image)

A = (4 x 6) + (12 x [7 + 7 + 4])
A = (24) + (12 x 18)
A = 24 + 216
A = 240cm^2

I hope this helped? Comment if you need more explanation or anything!

8 0
2 years ago
a) What is the probability that a person selected at random from the general population is senior citizen who will get the flu t
Greeley [361]
<span>The probability that a person selected at random from the general population is senior citizen who will get the flu this season is 0.14 x 0.18 = 0.0252</span>
7 0
3 years ago
Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
2 years ago
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