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s344n2d4d5 [400]
3 years ago
9

Help me with this!!! Fake answers will get reported

Mathematics
1 answer:
zlopas [31]3 years ago
6 0

Answer:

Step-by-step explanation:

there is an obscure rule that looks like this

DB/AB = AB/CB

AB=40 for this problem

DB = x

CB = 20

then

X/40 = 40/20

X = 40(40/20)

X = 40(2)

X=80

I find that hard to believe too,   :D

but the rule says that's right

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Answer:

P(-8,6), Q(-5,2), R(2,1)

8 0
3 years ago
Multiple Choice [x] + 5 = 18 A 5 or -5 B. 13 or -13 ​
Charra [1.4K]

Answer: don't know sorry

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
(i) 3 (a + 5b) + a (a + 4) (ii) y (10 - y) + 3 (y - 2) (iii) 2 (8a - 5b) + 3 (5a - 12) (iv) 3 (y - 3) + ( 8 - 6y + x) (v) a (a -
AveGali [126]

Answer:

3 (a + 5b) + a (a + 4)  = a^2 + 7a + 15b

y (10 - y) + 3 (y - 2)  = - y^2+13y - 6

2 (8a - 5b) + 3 (5a - 12)  = 31a -10b  - 36

3 (y - 3) + ( 8 - 6y + x) = -3y + x-1

a (a - 2b) + b (b + 2a - c) =a^2  + b^2  - bc

5 (x - y + z) + (4x + 3y) =9x - 2y +5z

Step-by-step explanation:

Solving (i):

3 (a + 5b) + a (a + 4)

Open brackets

3 (a + 5b) + a (a + 4)  = 3a + 15b + a^2 + 4a

Collect like terms

3 (a + 5b) + a (a + 4)  = a^2 + 4a+3a + 15b

3 (a + 5b) + a (a + 4)  = a^2 + 7a + 15b

Solving (ii)

y (10 - y) + 3 (y - 2)

Open bracket

y (10 - y) + 3 (y - 2)  = 10y - y^2 + 3y - 6

Collect like terms

y (10 - y) + 3 (y - 2)  = - y^2+10y  + 3y - 6

y (10 - y) + 3 (y - 2)  = - y^2+13y - 6

Solving (iii)

2 (8a - 5b) + 3 (5a - 12)

Open bracket

2 (8a - 5b) + 3 (5a - 12)  = 16a -10b + 15a - 36

Collect like terms

2 (8a - 5b) + 3 (5a - 12)  = 16a+ 15a -10b  - 36

2 (8a - 5b) + 3 (5a - 12)  = 31a -10b  - 36

Solving (iv)

3 (y - 3) + ( 8 - 6y + x)

Open bracket

3 (y - 3) + ( 8 - 6y + x) = 3y - 9 + 8 - 6y + x

Collect like terms

3 (y - 3) + ( 8 - 6y + x) = 3y  - 6y + x- 9 + 8

3 (y - 3) + ( 8 - 6y + x) = -3y + x-1

Solving (v):

a (a - 2b) + b (b + 2a - c)

Open bracket

a (a - 2b) + b (b + 2a - c) =a^2 - 2ab + b^2 + 2ab - bc

Collect like terms

a (a - 2b) + b (b + 2a - c) =a^2 + 2ab- 2ab + b^2  - bc

a (a - 2b) + b (b + 2a - c) =a^2  + b^2  - bc

Solving (vi)

5 (x - y + z) + (4x + 3y)

Open brackets

5 (x - y + z) + (4x + 3y) =5x - 5y +5z+4x +3y

Collect like terms

5 (x - y + z) + (4x + 3y) =5x +4x +3y- 5y +5z

5 (x - y + z) + (4x + 3y) =9x - 2y +5z  

6 0
3 years ago
Please hurry, 15 points and it's overdue.
valina [46]

Answer:

The relationship is positive.

The model predicts a score of 60.

Not sure what part b is.

Step-by-step explanation:

Since while the money spent on advertising increases while the items sold increases, we have a positive relation between both variables.

By looking at where 30 is on the graph, we can see it lines up with 60,the middle between $40 and $80 on the y axis and so we know this is the cost associated with this value.

4 0
3 years ago
PLEASE HELP (AGAIN) LOOK AT PIC
Serhud [2]

Answer: it should be 60

Step-by-step explanation:

6 0
3 years ago
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