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AysviL [449]
3 years ago
8

A greeting card uses a geometric design containing 4 congruent kites. The card is 4 inches wide and 8 inches long. What is the a

rea of one kite? 4 sq. in. 8 sq. in. 12 sq. in. 16 sq. in.
Mathematics
2 answers:
Gnom [1K]3 years ago
3 0

Answer: 4 sq. in

Step-by-step explanation:

From the question, the card is 8 inches long. Therefore, the length of the vertical diagonal of 1 kite + the length of the vertical diagonal of other kite = 8

Since we have been told that the kites are congruent, therefore the length of the vertical diagonal of both kites will be thesame

Therefore, 2(length of the vertical diagonal of 1 kite) = 8

Therefore, the length of the vertical diagonal of 1 kite will be= 4 inches

The width of the card = 4 inches

Therefore, the length of the horizontal diagonal of 1 kite + the length of the horizontal diagonal of another kite =4

Since the kites are congruent, therefore, the length of the horizontal diagonal of both kites are the same

Therefore, 2(length of the horizontal diagonal of 1 kite) = 4

Therefore, the length of the horizontal diagonal of 1 kite will be= 2 inches

Therefore, the length of the vertical diagonal of the kite= 4 inches and the horizontal diagonal= 2 inches

So, Area of kite = pq/2

Where p and q are diagonals of kite

Area of kite = (4×2)/2

=8/2

= 4 inches square

dimaraw [331]3 years ago
3 0

Answer:

A 4

Step-by-step explanation:

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