sum of angle of straight line is 180°. So, x+90°+25°=180°,. x+115°=180°.,. x=180°-115°, X=65°. so, the second option is correct 65°
supplementary angles = 180 degrees
so x = angle 1
y = angle 2
y = 3x-12
x + 3x-12 =180
4x-12 = 180
4x = 192
x = 192/4 = 48
y = 3(48) -12 = 144-12 = 132
132 +48 = 180
the angle is 132
Answer:its a zero slope or you can do x2-x1 and y2-y1 and if its an even fraction try simplifying it .
Step-by-step explanation:
Answer: A
Step-by-step explanation: you go 10 to the 8th^, and 10 to the 6th^
Complete question is;
The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?
Answer:
csc θ = -13/12
Step-by-step explanation:
We know that in a unit circle;
(x, y) = (cos θ, sin θ)
Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;
cos θ = -10/26
sin θ = -24/26
Now we want to find csc θ.
From trigonometric ratios, csc θ = 1/sin θ
Thus;
csc θ = 1/(-24/26)
csc θ = -26/24
csc θ = -13/12
