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3 years ago

Please help and show your work, will mark brainliest

Mathematics

1 answer:

Alja [10]3 years ago

8 0

Answer:

y = -2x + 9 y =1/9x + 4/9

Step-by-step explanation:

-9/2 = -x -1/2y

-1/2y = x - 9/2

y = -2x + 9

-4 - x = -9y

-9y = -4 - x

y = 1/9x + 4/9

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A 30inch piece of wood is 3% of a longer piece of wood. How long is the longer piece of wood?

Shtirlitz [24]

Answer:

1,000 inches

Step-by-step explanation:

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3 years ago

If √7 = 2.646, find without using calculator,<br>the value<br>of<br>√0.0007

Varvara68 [4.7K]

Answer:

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Step-by-step explanation:

We know that:

√7 = 2.646

We want to find the value of:

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$\frac{\sqrt{x} }{\sqrt{y} } = \sqrt{\frac{x}{y} }$

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3 years ago

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3 years ago

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DanielleElmas [232]

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3 years ago

(t-distribution) A manufacturing firm claims that the batteries used in laptop computers will last an average of 50 months. To m

statuscvo [17]

Answer:

There is an 38.21% probability that we find this lifespan for our sample average, or something even shorter.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A manufacturing firm claims that the batteries used in laptop computers will last an average of 50 months. This means that $\mu = 50$ .

We found that the sample had a average lifespan of 47.3 months, and a standard deviation of s = 9 months. What is the probability that we find this lifespan for our sample average, or something even shorter?

We have to find the pvalue of Z when $X = 47.3$ .

We are working with a sample mean, so we use the standard deviation of the sample in the place of $\sigma$ . That is $s = 9$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{47.3-50}{9}$

$Z = -0.3$

$Z = -0.3$ has a pvalue of 0.3821.

There is an 38.21% probability that we find this lifespan for our sample average, or something even shorter.

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3 years ago