Please helpppp fasttt please explain because i dont know how to do this
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By Green's theorem, the line integral
is equivalent to the double integral
where <em>D</em> is the region bounded by the curve <em>C</em>, provided that this integrand has no singularities anywhere within <em>D</em> or on its boundary.
It's a bit difficult to make out what your integral should say, but I'd hazard a guess of
Then the region <em>D</em> is
<em>D</em> = {(<em>x</em>, <em>y</em>) : 0 ≤ <em>x</em> ≤ 1 and <em>x</em> ² ≤ <em>y</em> ≤ √<em>x</em>}
so the line integral is equal to
which in this case is 7 times the area of <em>D</em>.
The remaining integral is trivial:
Answer:
Following are the response to the given points:
Step-by-step explanation:
For question 5.11:
For point a:
For all the particular circumstances, it was not an appropriate sampling strategy as each normal distribution acquired is at a minimum of 30(5) = 150 or 2.5 hours for a time. Its point is not absolutely fair if it exhibits any spike change for roughly 10 minutes.
For point b:
The problem would be that the process can transition to an in the state in less than half an hour and return to in the state. Thus, each subgroup is a biased selection of the whole element created over the last hours. Another sampling approach is a group.
For question 5.12:
This production method creates 500 pieces each day. A sampling section is selected every half an hour, and the average of five dimensions can be seen in a line graph when 5 parts were achieved.
This is not an appropriate sampling method if the assigned reason leads to a sluggish, prolonged uplift. The difficulty would be that gradual or longer upward drift in the procedure takes or less half an hour then returns to a controlled state. Suppose that a shift of both the detectable size will last hours . An alternative type of analysis should be a random sample of five consecutive pieces created every
hour.