All categories

3 years ago

Y = 5x + 8; if x = 3 helppp

Mathematics

2 answers:

densk [106]3 years ago

8 0

Answer:

y=23

Step-by-step explanation:

Given , y=5x+8 if x=3

y= 5×3+8

y=15+8

y=23

.'. y=23 is Ans

Katyanochek1 [597]3 years ago

3 0

Y = 5 x 3 + 8
y = 15 + 8
y = 23

You might be interested in

Which angle is an x–intercept for the function y=cos(1/2x)? A. 0 B. pie/2 C. pie D. 2pie

Neporo4naja [7]

Answer:

For the function

y = cos(1/2 x)

The x-intercept can be calculated by equating the function to zero and solving for x. So,

y = cos(1/2 x) = 0

1/2 x = arc cos 0

1/2 x = 90° +180°n

x =2 (90° +180°n)

x = 180° + 360°n

or converting to radians

x = (180° + 360° n)(π/180°)

x = π + 2π n

where n is any whole number

if n = 0

x = π

Therefore, the x-intercept is π or π+2π n

Step-by-step explanation:

Plz give me brainleist worked hard thanks

6 0

2 years ago

Read 2 more answers

Show Your Work<br> Please help I’ll mark brainliest

fgiga [73]

Answer:

(c)

Step-by-step explanation:

3+2+4 = 9, 4+2= 6- 3= 3

3 0

3 years ago

The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.

MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle = $3\times\ side$

$3\times\ side$ $=[tex]81\sqrt{3}$

$Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm$

Thus from the diagram , Side $AB=BC=AC= 27\sqrt{3} \ cm$

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus $\angle OBC = 30$ °

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

$tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2} } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\$

Thus ,apothem OE= 13.5 cm

Now for radius,

We consider ΔOBE

$cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB} \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm$