Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
Answer:
Step-by-step explanation:
Let a be the length of the altitude, then from the given triangles, applying the basic proportionality theorem, we get
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Thus, the length of altitude is: 12 cm.
Now, 
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Also, 
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Thus, the lengths of the legs of this triangle are 14.83 and 20 cm.
Answer:
1/2 of the cookies are peanut butter.
Step-by-step explanation:
Since 1/4 of the cookies are chocolate chip, this leaves the other 3/4 of the jar, which is equivallent to 75/100. Since 2/3 of 75 is 50, or, 1/2, the answer is 1/2.
