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2 years ago

Helppppppp...?????????????????????

Mathematics

1 answer:

Angelina_Jolie [31]2 years ago

4 0

Answer:

144(3/4)^1-n

Step-by-step explanation:

This is a geometric sequence, so if you divide 192 by 144 you will find that the common ratio r is 4/3. This would make the equation an=144(4/3)^n-1. However, that's not one of the options. If you plug in some numbers, you can see that 3/4 (the reciprocal of 4/3) can work as well if it's 3/4^1-n. 4/3^-1=3/4 and n-1(-1)=1-n

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Chart and assignment above, any actual help is appreciated!! Eighth grade math :)

Minchanka [31]

1. Car Mart sell 11 cars per day.
You can use the table by looking at day 2 and day 3. You can see underneath it, it shows how many cars is left after that particular day. So from day 2, you have 43 cars left and day 3, you got 32 cars left. From 43 car to 32 car is losing 11 car. So each day the Car Mart sell 11 car.

2. First we know that after 3 days, Winston have 32 cars left and after 5 day, it has 12 cars left.
Here’s the chart that I made for Winston:
Each day, Winston’s sell 10 cars. (Lose 10 cars per day)

4 0

3 years ago

Health insurance benefits vary by the size of the company (the Henry J. Kaiser Family Foundation website, June 23, 2016). The sa

xxMikexx [17]

Answer:

$\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.221)=0.000067$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example $\alpha=0.05$ , we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

Assume the following dataset:

Size Company/ Heal. Ins. Yes No Total

Small 32 18 50

Medium 68 7 75

Large 89 11 100

_____________________________________

Total 189 36 225

We need to conduct a chi square test in order to check the following hypothesis:

H0: independence between heath insurance coverage and size of the company

H1: NO independence between heath insurance coverage and size of the company

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{50*189}{225}=42$

$E_{2} =\frac{50*36}{225}=8$

$E_{3} =\frac{75*189}{225}=63$

$E_{4} =\frac{75*36}{225}=12$

$E_{5} =\frac{100*189}{225}=84$

$E_{6} =\frac{100*36}{225}=16$

And the expected values are given by:

Size Company/ Heal. Ins. Yes No Total

Small 42 8 50

Medium 63 12 75

Large 84 16 100

_____________________________________

Total 189 36 225

And now we can calculate the statistic:

$\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.221)=0.000067$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

3 0

3 years ago

This is my last question I have 6 minutes remaining, help me please <br><br> ASAP no rocky

dimaraw [331]

Answer:

rationalizing

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The equation Ax+By=10 goes through the coordinates (6,5) and (-2,-5).What are the values of A and B

wolverine [178]

Given:

The equation $Ax+By=10$ goes through the coordinates (6,5) and (-2,-5).

To find:

The values of A and B.

Solution:

We have,

$Ax+By=10$

It goes through the coordinates (6,5) and (-2,-5). It means these points will satisfy the equation.

$A(6)+B(5)=10$

$6A+5B=10$ ...(i)

$A(-2)+B(-5)=10$

$-2A-5B=10$ ...(ii)

Adding (i) and (ii), we get

$(6A+5B)+(-2A-5B)=10+10$

$4A=20$

Divide both sides by 4.

$A=5$

Put A=5 in (i), we get

$6(5)+5B=10$

$30+5B=10$

$5B=10-30$

$5B=-20$

Divide both sides by 5.

$B=-4$

Therefore, the values of A and B are 5 and -4 respectively.

3 0

2 years ago

What is the area of the wall that will be painted

svp [43]

Answer:

B. 104

Step-by-step explanation:

Just find the area of the wall and subtract the area of the window. The area of the wall is 10 times 11 which is 110. The area of the window is 2 times 3 which is 6. 110 minus 6 is 104.

6 0

3 years ago