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Rama09 [41]
2 years ago
14

Helppppppp...?????????????????????

Mathematics
1 answer:
Angelina_Jolie [31]2 years ago
4 0

Answer:

144(3/4)^1-n

Step-by-step explanation:

This is a geometric sequence, so if you divide 192 by 144 you will find that the common ratio r is 4/3. This would make the equation an=144(4/3)^n-1. However, that's not one of the options. If you plug in some numbers, you can see that 3/4 (the reciprocal of 4/3) can work as well if it's 3/4^1-n. 4/3^-1=3/4 and n-1(-1)=1-n

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Monica wrote a 5 digit number 12,335 then circled the digit 3 on the right. which other digit in the number has a value that is
Snowcat [4.5K]
Digit 3 on the 10 side has a value of 3 tens or 30. We want to find the digit that has exactly 10 times that value. well, 10 × 30 = 300. So which digit has the value of 300? The other 3 is in the 100's place and it's value is 3 one hundreds or 300. So that is your digit... the 3 in the hundreds place.
6 0
3 years ago
Which expression is equivalent to<br> 0 +<br> 2<br> 29<br> C+3<br> C+2<br> C+3<br> C+2
Kryger [21]

Answer:

C+3

Step-by-step explanation:

6 0
3 years ago
Solve The Equation <br> 4x×9y=7<br> 4x-9y=9
hoa [83]

Answer:

\large\boxed{x=\dfrac{9}{8}-\dfrac{\sqrt{109}}{8},\ y=-\dfrac{1}{2}-\dfrac{\sqrt{109}}{18}}\\or\\\boxed{x=\dfrac{9}{8}+\dfrac{\sqrt{109}}{2},\ y=-\dfrac{1}{2}+\dfrac{\sqrt{109}}{18}}

Step-by-step explanation:

\left\{\begin{array}{ccc}4x\times9y=7&(1)\\4x-9y=9&(2)\end{array}\right\\\\(2)\\4x-9y=9\qquad\text{subtract}\ 4x\ \text{from both sides}\\-9y=-4x+9\qquad\text{change the signs}\\9y=4x-9\qquad\text{substitute it to (1)}\\\\4x(4x-9)=7\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\(4x)(4x)+(4x)(-9)=7\\(4x)^2-36x=7\\(4x)^2-2(4x)(4.5)=7\qquad\text{add}\ 4.5^2\ \text{to both sides}\\(4x)^2-2(4x)(4.5)+4.5^2=7+4.5^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2

(4x-4.5)^2=7+20.25\\(4x-4.5)=27.25\to 4x-4.5=\pm\sqrt{27.25}\\\\4x-\dfrac{45}{10}=\pm\sqrt{\dfrac{2725}{100}}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{2725}}{\sqrt{100}}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{25\cdot109}}{10}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{25}\cdot\sqrt{109}}{10}\\\\4x-\dfrac{45}{10}=\pm\dfrac{5\sqrt{109}}{10}\qquad\text{add}\ \dfrac{45}{10}\ \text{to both sides}\\\\4x=\dfrac{45}{10}\pm\dfrac{5\sqrt{109}}{10}

4x=\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}\qquad\text{divide both sides by 4}\\\\x=\dfrac{9}{8}\pm\dfrac{\sqrt{109}}{8}\\\\\text{Put the values of}\ x\ \text{to (2):}\\\\9y=4\left(\dfrac{9}{8}\pm\dfrac{\sqrt{109}}{8}\right)-9\\\\9y=\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}-\dfrac{18}{2}\\\\9y=-\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}\qquad\text{divide both sides by 9}\\\\y=-\dfrac{1}{2}\pm\dfrac{\sqrt{109}}{18}

8 0
3 years ago
A bag contains 15 green, 18 yellow, and 16 orange balls. One ball is randomly selected.
sergeinik [125]

Answer:

Green: 15/49

Yellow: 18/49

Orange: 16/49

Step-by-step explanation:

Add the total amt. of balls, then divide a specific group of balls by the total # of balls to get the ratios.

5 0
3 years ago
.........................
Zigmanuir [339]

Answer:

A

Step-by-step explanation:

given 3xy + 4yz + 8xz = 10

subtract 8xz from both sides leaving the terms in y together

3xy + 4yz = 10 - 8xz

take out the common factor y on the left side

y(3x + 4z) = 10 - 8xz

divide both sides by (3x + 4z)

y = \frac{10-8xz}{3x+4z} → A


5 0
3 years ago
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