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ohaa [14]
3 years ago
7

If N > 9 the decimal equivalent is _______ Repeating

Mathematics
1 answer:
Drupady [299]3 years ago
7 0

Answer:

Wouldnt it just be 10 lol? there is no decimal equivalent

Step-by-step explanation:

You might be interested in
Find the missing angles... both 4 and 5 separately
Oliga [24]

Answer:

4 : 34

5 : 102

Step-by-step explanation:

This problem can be solved by using concept of co-interior angles.

co interior angles are those angles which lie on the same of parallel lines when the parallel lines are cut by transversal.

sum of co interior angles is 180 degrees.

In the problem 4 and 5 then angle given and missing angles are co-interior angles.

Problem 4

146 + ? = 180

? = 180 -146 = 34

Thus missing  angle in problem 4 is 34 degrees

Problem 5

78 + ? = 180

? = 180 -78 = 102

Thus missing  angle in problem 5 is 102 degrees

4 0
3 years ago
Select the equation that has the same solution as the equation below.<br> 5^(2x-5)= 125
Ahat [919]

The equation that has the same solution as 5^{(2x-5)} = 125 is: C.64 = 2^{(3x - 6)}

<h3>How to Solve Equations having Exponents</h3>
  • To solve such, simplify the bases so that the base on the right equals the base on the left.
  • Then solve the equation for the variable.

Given:

5^{(2x-5)} = 125\\\\5^{(2x-5)} = 5^3\\

  • The bases will cancel out

2x - 5 = 3

  • Solve for x

2x = 3 + 5

2x = 8

x = 4

The solution of 5^{(2x-5)} = 125 is 4.

Thus:

64 = 2^{(3x - 6)}\\\\2^6 = 2^{(3x - 6)}\\\\6 = 3x - 6\\6 + 6 = 3x\\12 = 3x\\4 = x\\x = 4

Therefore the equation that has the same solution as 5^{(2x-5)} = 125 is: C.64 = 2^{(3x - 6)}

Learn more about equations with exponents on:

brainly.com/question/11832081

3 0
2 years ago
Find the number of real number solutions for the equation x^2-3+8=0
svlad2 [7]
Find value of determinant.
The determinant is a term that is inside a square root and part of the quadratic formula used for solving quadratic equations.
Let determinant be 'd'.
If d >0, Then there are 2 real solutions
If d = 0, Then there is only 1 real solutions
If d < 0, Then there are 0 real solutions but 2 imaginary solutions

d = b^2 - 4ac

For this problem, the coefficients are:
a = 1, b = -3, c = 8

d = (-3)^2 - 4(1)(8)

d = 9 -32 = -23

d is less than 0, therefore there are 0 real solutions and 2 imaginary solutions.

This is true because you cannot take square root of a negative number.



5 0
3 years ago
What is the product?<br> (-3s+2t)(4s-t)
Marizza181 [45]

Answer:

12s² + 11st - 2t²

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, that is

- 3s(4s - t) + 2t(4s - t) ← distribute both parenthesis

= - 12s³ + 3st + 8st - 2t² ← collect like terms

= - 12s² + 11st - 2t²

5 0
3 years ago
Read 2 more answers
PLEASE ANSWER ASAP
ss7ja [257]

Answer:

Approximately 0.51

Step-by-step explanation:

3 0
2 years ago
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