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3 years ago

Name the 3 elements, in order, that make up a very important part of Thanksgiving. (Spell out a word with chemical symbols)

Chemistry

2 answers:

melomori [17]3 years ago

7 0

Answer:

Chemical element symbols are one- and two-letter abbreviations for the element names. They are used to make the periodic table and chemical formulas easier to read. You can combine the symbols to make words. Here is a list of English words made from periodic table element symbols. There are thousands of words that can be written using these symbols, so experiment to see if you can write your name or fun messages that show your chemistry savvy.

7nadin3 [17]3 years ago

3 0

Answer:

eat well, stay well, and have fun ∛π⇅πΔΔΔ≅≅⇵↑↓∫∫↑

Explanation:

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Does food passes through liver, pancreas and appendix?

Ksivusya [100]

Answer: yes

Explanation:

6 0

3 years ago

Read 2 more answers

A water treatment tablet contains 20.0 mg of tetraglycine hydroperiodide, 40.0% of which is available as soluble iodine. If two

Galina-37 [17]

Answer:

$16\ \text{ppm}$

Explanation:

Mass of one tablet = 20 mg

Mass of two tablets = $2\times 20=40\ \text{mg}$

Percent that is soluble in water = 40%

Mass of tablet that is soluble in water = $0.4\times 40=16\ \text{mg}$

So, mass of solute is $16\ \text{mg}$

Density of water = 1 kg/L

Volume of water = 1 L

So, mass of 1 L of water is $1\times 1=1\ \text{kg}=1000\ \text{g}$

PPM is given by

$\dfrac{\text{Mass of solute}}{\text{Mass of solvent}}\times 10^6=\dfrac{16\times 10^{-3}}{1000}\times 10^6\\ =16\ \text{ppm}$

Hence, the concentration of iodine in the treated water $16\ \text{ppm}$ .

8 0

3 years ago

Each hydrogen atom contains ___ protons.

MA_775_DIABLO [31]

1
8
1
2
Covalent
6
Inner
Sorry don’t understand the last question

7 0

3 years ago

Read 2 more answers

A constant-volume calorimeter was calibrated by carrying out a reaction known to release 3.50 kJ of heat in 0.200 L of solution

Dmitrij [34]

Answer:

The change in internal energy is - 1.19 kJ

Explanation:

Step 1: Data given

Heat released = 3.5 kJ

Volume calorimeter = 0.200 L

Heat release results in a 7.32 °C

Temperature rise for the next experiment = 2.49 °C

Step 2: Calculate Ccalorimeter

Qcal = ccal * ΔT ⇒ 3.50 kJ = Ccal *7.32 °C

Ccal = 3.50 kJ /7.32 °C = 0.478 kJ/°C

Step 3: Calculate energy released

Qcal = 0.478 kJ/°C *2.49 °C = 1.19 kJ

Step 4: Calculate change in internal energy

ΔU = Q + W W = 0 (no expansion)

Qreac = -Qcal = - 1.19 kJ

ΔU = - 1.19 kJ

The change in internal energy is - 1.19 kJ

4 0

4 years ago

Consider the following balanced equation:

Serga [27]

Zn⁰ + 2H⁺ ------> Zn²⁺ + H2⁰

H⁺ ion has oxidation number +1.
Zn²⁺ ion has oxidation number +2.
Atom of Zn has electric charge 0, and each hydrogen atom in the molecule H2 have oxidation number 0. So, Zn and each hydrogen atom in H2 have oxidation numbers equals "0".

Answer is
D. Zn and each hydrogen atom in H2

4 0

4 years ago