All categories

3 years ago

If I plant a green bean seed in the desert, will it grow thick, barrel-shaped stems full of water like a cactus? Why or why not?

Chemistry

1 answer:

Ket [755]3 years ago

8 0

Answer:

No, although the bean crop can grow perfectly in full sun or a little shade in very warm places. It does not mean that they will adopt the growth patterns of the cactus, especially because this plant needs constant watering (in small quantities), very constant. Beans require good drainage for their growth.

You might be interested in

Write balanced molecular, ionic, and net ionic equations for the reaction occurs when (a) a BaCl2 (Barium Chloride) is mixed wit

lubasha [3.4K]

A.) We write the molecular equation for the chemical reaction as:

BaCl2(aq)+Na2SO4(aq)→BaSO4(s)⏐+2NaCl(aq)

Alternatively, we could write the net ionic equation:

Ba2+ + SO2^−4→ BaSO4(s)⏐

B.)We write the molecular equation for the chemical reaction as:

Ba(OH)^2 + 2HBr → BaBr2 + 2H2O

The ionic equation can be written as;

Ba^2+ + 2OH^- + 2H^+ + 2Br^- →

Ba^2+ + 2Br^- + 2H2O

the net ionic equation can be written as;

2OH^- + 2H^+ → 2H2O

Alternatively, we could write the net ionic equation

OH^-(aq) + H^+(aq) → H2O(l) net ionic equation.

C.) We write the molecular equation for the chemical reaction as:

2 HNO2(aq) + Ba(OH)2(aq) 

→ Ba(NO2)2(aq) + 2 H2O(l)

Net ionic equation

HNO2(aq) + OH-(aq) → NO2-(aq) + H2O(l)

Alternatively, we could write the net ionic equation as:

2H^+ + 2OH → 2H2O

8 0

4 years ago

How many hydrogen atoms are in the compound represented by the following bond-line drawing?<br> ОН

Ganezh [65]

Answer:

Theres no drawing

Explanation:

Show drawing

4 0

3 years ago

An electron charge e mass m and a positron charge e mass m revolve around their common center of mass under the influence of the

Katen [24]

Answer: v = 2π2 Kme2 Z / nh

Explanation:

The formula for velocity of an electron in the nth orbit is given as,

v = 2π2 Kme2 Z / nh

v = velocity

K = 1/(4πε0)

m= mass of an electron

e = Charge on an electron

Z= atomic number

h= Planck’s constant

n is a positive integer.

3 0

4 years ago

Tin(IV) sulfide, SnS2, a yellow pigment, can be produced using the following reaction.

Maksim231197 [3]

The theoretical yield of $SnS_2$ will be 4.20 grams while the percent yield will be 7.93%

<h3>How is yield calculated?</h3>

From the equation of the reaction, the mole ratio of $SnBr_4$ to $Na_2S$ is 1:2.

Mole of 48.1 mL, 0.478 M $SnBr_4$ = 0.478 x 48.1/100 = 0.023 mols

Mole of 48.8 mL, 0.160 M $Na_2S$ = 0.160 x 48.8/1000 = 0.0078 moles

$SnBr_4$ $Na_2S$ is the limiting reactant.

Mole ratio of $SnBr_4$ and $SnS_2$ = 1:1

Equivalent mole of $SnS_2$ = 0.023 moles

Mass of 0.023 noles $SnS_2$ = 0.023 x 182.81 = 4.20 grams

With 0.0333 g of $SnS_2$ recovered, percent yield = 0.333/4.2 x 100 = 7.93%

More on yields of reactions can be found here: brainly.com/question/17042787

#SPJ1

Tin(IV) sulfide, SnS2, a yellow pigment, can be produced using the following reaction.

SnBr4(aq)+2Na2S(aq)⟶4NaBr(aq)+SnS2(s)

Suppose a student adds 48.1 mL of a 0.478 M solution of SnBr4 to 48.8 mL of a 0.160 M solution of Na2S.

1) Calculate the theoretical yield of SnS2. ;

2) The student recovers 0.333 g of SnS2. Calculate the percent yield of SnS2 that the student obtained.

7 0

2 years ago

What does it mean SI unit in chemistry

Viefleur [7K]

All
International System of Units

8 0

3 years ago

Read 2 more answers