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3 years ago

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Father is four times as old as Mary. Five years ago he was seven times as old. How old is the father now?

1 answer:

melamori03 [73]3 years ago

7 0

Answer:

If Father is four times older than Mary, that would be 4 times 10-- which equals 40. Five years ago, Mary must have been 5 years old. So, multiply 7 and 5 and you'll get 35! Father would have been 35 years old.

I hope this helps!

Step-by-step explanation:

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If Jeremy is feeding his Chihuahua 1/2 cup of dog food but uses 1/10 of a cup, how many scoops will he need to feed his dog?

agasfer [191]

Answer: 5

Step-by-step explanation:

The question is asking how many tenths are in one half. You need to divide one half by one tenth. To divide fractions you need to invert and multiply.

1/2 ÷ 1/10

Step 1: Invert and multiply

1/2 × 10/1 = 10/2

Step 2: Simplify

10/2 = 5

6 0

3 years ago

The equation p=1.5r graphed find price p, in dollars for r pounds of rice

disa [49]

Answer:

Hope that help you mark me brinilylist

Step-by-step explanation:

Given that 5 pounds of rice at a store cost $6.50.

Then 1 pound of rice at a store cost = $6.50/5= $1.3

So the equation for the cost can be written as:

C=1.3P just like we write equation y=mx

Now we have to graph the cost C, vs pounds of rice.

Variable for Pounds of rice is not given so let it be "P"

So let's make a table for the number of pounds (P) and cost (C) we can graph the points from that table to get the final graph.

The Attached graph is the final graph.

3 0

3 years ago

Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are 36 and 2304, respectively.

poizon [28]

Answer:

$a_n=9(4^{n-1})$

Step-by-step explanation:

we know that

In a <u>Geometric Sequence</u> each term is found by multiplying the previous term by a constant, called the common ratio (r)

In this problem we have

$a_2=36\\ a_5=2,304$

Remember that

$a_2=a_1(r)$ -----> $36=a_1(r)$ -----> equation A

$a_5=a_4(r)$

$a_5=a_3(r^{2})$

$a_5=a_2(r^{3})$

Substitute the values of a_5 and a_2 and solve for r

$2,304=36(r^{3})$

$r^{3}=2,304/36$

$r^{3}=64$

$r=4$

Find the value of a_1 in equation A

$36=a_1(4)$

$a_1=9$

therefore

The explicit rule for the nth term is

$a_n=a_1(r^{n-1})$

substitute

$a_n=9(4^{n-1})$

3 0

3 years ago

Help! Pls I cant solve it help me with explanation also pls.

stich3 [128]

Given:

The expression is

$\dfrac{2}{a-2}-\dfrac{8}{a^2-4}$

To find:

The simplified form of the given expression.

Solution:

We have,

$\dfrac{2}{a-2}-\dfrac{8}{a^2-4}$

It can be written as

$=\dfrac{2}{a-2}-\dfrac{8}{a^2-2^2}$

$=\dfrac{2}{a-2}-\dfrac{8}{(a-2)(a+2)}$ $[\because a^2-b^2=(a-b)(a+b)]$

Taking LCM, we get

$=\dfrac{2(a+2)-8}{(a-2)(a+2)}$

$=\dfrac{2a+4-8}{(a-2)(a+2)}$

$=\dfrac{2a-4}{(a-2)(a+2)}$

$=\dfrac{2(a-2)}{(a-2)(a+2)}$

Cancel out the common factors.

$=\dfrac{2}{a+2}$

Therefore, the simplified form of the given expression is $\dfrac{2}{a+2}$ .

7 0

3 years ago

What is an expression equivalent to 9(47) using the distributive property?

pickupchik [31]

The answer is 9(40+7)

7 0

3 years ago