Dividing abc, which is a*b*c, we get 3*a/a*b/b*c/c=3
You are right
Use the Pythagorean theorem
3^2+12^2=153
sqrt153= 12.37
$10.66 is how much you going to play.
Answer:
21 quarters and 23 nickels. The quarters value at $5.25 and the nickels value at $1.15.
Step-by-step explanation:
This situation has two unknowns - the total number of nickels and the total number of quarters. Because we have two unknowns, we will write a system of equations with two equations using the two unknowns.
- is an equation representing the total number of coins
- is an equation representing the total value in money based on the number of coin. 0.05 and 0.25 come from the value of a nickel and quarter individually.
We write the first equation in terms of q by subtracting it across the equal sign to get . We now substitute this for n in the second equation.
After simplifying, we subtract 2.2 across and divide by the coefficient of q.
We now know of the 44 coins that 21 are quarters. To find the total value of the quarters, we multiply 21 by 0.25 and find 5.25.
Since there are 21 quarters out of 44, there must be 23 nickels. To find the total value of the nickels, we multiply 23 by 0.05 and find 1.15.
Answer:
The width of lot B is 11 feet, so option A is correct.
Step-by-step explanation:
Given:
- Two rectangular properties share a common side.
- Lot A is 33 feet wide and 42 feet long.
- The combined area of the lots = 1,848 square feet.
To find:
How many feet wide is Lot B?
Solution:
we know that, area of a rectangle is length x breadth
Then area of lot A = 33 x 42 = 1386 square feet.
And area of lot B = width x 42
Now, we are given that, total area = 1848
area of lot A + area of lot B = 1848
1386 + width x 42 = 1848
width x 42 = 1848 – 1386
width x 42 = 462
width = 11
Hence, the width of lot B is 11 feet, so option A is correct.