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Hoochie [10]
3 years ago
11

guys pls i post two more questions that i dont kno and i want to pass my test sorry ,but they are important

Mathematics
1 answer:
Andrej [43]3 years ago
5 0
Okkk .. this is what this app is for anyways to help.
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PLSSSS HELP ME WITH THIS QUESTION!!!
AysviL [449]

Given,  

∠AOE = 30°

∠DOB = 40°

So, ∠EOD = 180 - (30+40)           [angles on a straight line]

                =  180 - 70

                =  110

∠EOD = ∠COF                             [ vertically opposite angle]

∴ ∠COF = 110°

7 0
3 years ago
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Tanzania [10]

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7 0
3 years ago
Simplify: (8)2(2)3 (4)3(-2)4 A) 1 2 B) 2 3 C) 2 9 D) 3 4
Digiron [165]

Answer:

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Step-by-step explanation:

6 0
3 years ago
How do you solve angle bisectors of triangles
katovenus [111]
You draw a circle from the tip of the triangle. Then you draw equal-sized circles from the points where the first circle intersects the triangle. Connect the tip of the triangle and the point where the equal-sized circles intersect each other.
5 0
4 years ago
If m< LMP is 11 degrees more than m< NMP and m< NML =137, find each measure
Agata [3.3K]

First, note that for angles LMP and NMP you have

m\angle LMP+m\angle NMP=m\angle NML.

If m\angle LMP is 11^{\circ} more than m\angle MNP, then

m\angle LMP=m\angle NMP+11^{\circ}.

Now, since m\angle MNL=137^{\circ}, you have

137^{\circ}=m\angle NMP+11^{\circ}+m\angle NMP,\\ \\2m\angle NMP=137^{\circ}-11^{\circ}=126^{\circ},\\ \\m\angle NMP=63^{\circ}.

Therefore,

m\angle LMP=63^{\circ}+11^{\circ}=74^{\circ}.

Answer: m\angle LMP=74^{\circ},\ m\angle NMP=63^{\circ}.


7 0
3 years ago
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