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Hoochie [10]
3 years ago
11

guys pls i post two more questions that i dont kno and i want to pass my test sorry ,but they are important

Mathematics
1 answer:
Andrej [43]3 years ago
5 0
Okkk .. this is what this app is for anyways to help.
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Find the exact value of sin(255∘)
Masteriza [31]

Check the picture below.

\textit{Sum and Difference Identities} \\\\ sin(\alpha + \beta)=sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(255^o)\implies sin(135^o+120^o) \\\\\\ sin(135^o)cos(120^o)~~ + ~~cos(135^o)sin(120^o) \\\\\\ \left( \cfrac{\sqrt{2}}{2} \right)\left( -\cfrac{1}{2} \right)~~ + ~~\left( -\cfrac{\sqrt{2}}{2} \right)\left( \cfrac{\sqrt{3}}{2} \right)\implies -\cfrac{\sqrt{2}}{4}~~ - ~~\cfrac{\sqrt{6}}{4}\implies \cfrac{-2-\sqrt{6}}{4}

5 0
2 years ago
What is the least common denominator for 1/2 & 2/3 ?
IrinaVladis [17]

Answer: 6

Step-by-step explanation:

1/2 = 3/6

2/3 = 4/6

4 0
3 years ago
10. Based on the diagram below, which statement is true?
Fofino [41]

Answer:

Part D is correct

Step-by-step explanation:

4 0
2 years ago
Please help me I stink at math need all
Elena L [17]
7) circle all of them8) write 1/the number it is seperatedby for all three and just divide the shapes evenly9) in thing order: no.no.yes,yes

5 0
3 years ago
In circle P, EG and FH are diameters.<br> What is m EH?
zvonat [6]

Answer:

m(\widehat{EH}) = 130°

Step-by-step explanation:

Angles subtended at the center by the arcs (\widehat{HG}) and (\widehat{EF}) are ∠HPG and  ∠EPF.

Since these angles are the vertical angles both will be equal.

m∠HPG ≅ m∠EPF

3x - 10 = 2x + 10

3x - 2x = 10 + 10

x = 20

Therefore, m(\widehat{HG})=(3\times 20) - 10

                               = 50°

Similarly m(\widehat{EF}) = 50°

In the same way angles subtended at the center will be equal.

m∠EPH ≅ m∠FPG

and m(\widehat{EH})=m(\widehat{FG})

Since m(\widehat{EH})+m(\widehat{FG})+m(\widehat{EF})+m(\widehat{HG})=360°

m(\widehat{EH})+m(\widehat{EH})+50+50=360

2m(\widehat{EH})=360-100

m(\widehat{EH})=130

Therefore, measure of arc EH = 130°

3 0
3 years ago
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