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NNADVOKAT [17]
4 years ago
9

7B%7D%5E%7B2%7D%20%7D%7B15%7D%20%20-%20%20%5Cfrac%7B%28a%20-%201%29%284%20-%20a%29%7D%7B5%7D%20%20%2B%20%20%5Cfrac%7B1%7D%7B5%7D%20" id="TexFormula1" title=" \frac{a(3 + a)}{3} \leqslant \frac{z(a - 1) {}^{2} }{15} - \frac{(a - 1)(4 - a)}{5} + \frac{1}{5} " alt=" \frac{a(3 + a)}{3} \leqslant \frac{z(a - 1) {}^{2} }{15} - \frac{(a - 1)(4 - a)}{5} + \frac{1}{5} " align="absmiddle" class="latex-formula">
can anyone help me?​
Mathematics
1 answer:
Sindrei [870]4 years ago
6 0
A= 15+z+ square root 17(z+15)/ z-2
z=2a^2/(a-1)^2 + 30a/(a-1)^2 - 15/(a-1)^2
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