Answer: In octet state.
Explanation: For noble gases they are stable in state since their outer shell contain fully occupied having 8 electrons.
They are *inverse* also the higher the frequency the greater the energy.
Mass spectrum of Dodecane will give following information.
1 ) Molecular Peak or Parent Peak:
The Parent peak will appear at m/z = 170. The intensity of this peak will be very weak.
2) Fragments:
Usually the fragments of such long chain alkanes appear with spacing of 14 amu, Hence, the peaks in dodecane will be as follow,
170 - 156 - 142 - 128 - 114 - 100 - 86 - 72 - 58 - 44 - 30 - 16
3) Base Peak:
Most probably the Base peak will appear at m/z = 57. This peak is due to the formation of tertiary butyl cation as the intensity mainly depends upon the stability of cation. So this cation might form due to rearrangment giving the intensity of 100%.
Answer:
a) 742.1 mm Hg O2
b) 0.4434 g O2
c) 0.01386 mol O2
Explanation:
<u>Step 1:</u> Data given
Mass of the sample = 3.6349 grams
volume of oxygen = 346.2 mL
Temperature = 23.6 °C
atmospheric pressure = 763.4 mmHg
<em><u>Step 2:</u></em><em> </em><em>What is the partial pressure of the oxygen? </em>
<em><u /></em>
763.4 mmHg - 21.3 mmHg = 742.1 mm Hg O2
<em>b. What mass of oxygen was liberated?</em>
All of the mass lost by the reactants was due to oxygen being liberated.
(3.6349 g) - ( 3.1915 g) = 0.4434 g O2
<em>c. How many moles of oxygen were produced?</em>
(0.4434 g O2) / (32 g O2/mol) = 0.01386 mol O2