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Varvara68 [4.7K]
3 years ago
9

What does the second law of thermodynamics say? O A. The entropy of the universe is increasing. B. A system at equilibrium has n

o entropy. C. The entropy of a system equals its enthalpy. D. All substances possess the same entropy.​
Chemistry
1 answer:
gayaneshka [121]3 years ago
7 0

Answer:

A.  The entropy of the universe is increasing.(always)

Explanation:

The Second Law of Thermodynamics states that Entropy cannot decrease, because it keeps increasing and increasing and increasing. It will always stay on the increasing side.

<u><em>Hope this helps!</em></u>

<u><em>Please Mark Brainliest!</em></u>

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Where’s the question or equation
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A sample of an unknown metal has a mass of 58.932g. it has been heated to 101.00 degrees C, then dropped quickly into 45.20 mL o
yaroslaw [1]
<h3>Answer:</h3>

0.111 J/g°C

<h3>Explanation:</h3>

We are given;

  • Mass of the unknown metal sample as 58.932 g
  • Initial temperature of the metal sample as 101°C
  • Final temperature of metal is 23.68 °C
  • Volume of pure water = 45.2 mL

But, density of pure water = 1 g/mL

  • Therefore; mass of pure water is 45.2 g
  • Initial temperature of water = 21°C
  • Final temperature of water is 23.68 °C
  • Specific heat capacity of water = 4.184 J/g°C

We are required to determine the specific heat of the metal;

<h3>Step 1: Calculate the amount of heat gained by pure water</h3>

Q = m × c × ΔT

For water, ΔT = 23.68 °C - 21° C

                       = 2.68 °C

Thus;

Q = 45.2 g × 4.184 J/g°C × 2.68°C

    = 506.833 Joules

<h3>Step 2: Heat released by the unknown metal sample</h3>

We know that, Q =  m × c × ΔT

For the unknown metal, ΔT = 101° C - 23.68 °C

                                              = 77.32°C

Assuming the specific heat capacity of the unknown metal is c

Then;

Q = 58.932 g × c × 77.32°C

   = 4556.62c Joules

<h3>Step 3: Calculate the specific heat capacity of the unknown metal sample</h3>
  • We know that, the heat released by the unknown metal sample is equal to the heat gained by the water.
  • Therefore;

4556.62c Joules = 506.833 Joules

c = 506.833 ÷4556.62

  = 0.111 J/g°C

Thus, the specific heat capacity of the unknown metal is 0.111 J/g°C

8 0
3 years ago
PLS HELP
serious [3.7K]

4. True

5. The amplitude of the ripples decreases as the circumference of the circle increases.

<h3>What is a wave?</h3>

A wave is a disturbance that moves energy from one place to another.

Radio waves, gamma-rays, visible light, and all the other parts of the electromagnetic spectrum are electromagnetic radiation. Electromagnetic radiation can be described in terms of a stream of mass-less particles, called photons, each travelling in a wave-like pattern at the speed of light. Hence, the statement is true.

As the disturbance moves outwards the energy it carries is spread over a larger and larger region called the wavefront. For example, the ripples in the water lie in a circle with an ever-increasing circumference. The amplitude of the ripples decreases as the circumference of the circle increases.

Learn more about the Electromagnetic wave here:

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Two different isotopes of the same element have : (true/false)
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Equal mass of an atom
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which bonds maintain the primary structure of a protein? question 7 options: ionic bonds hydrogen bonds peptide bonds disulfide
Mariulka [41]

Proteins have four structures primary, secondary,m tertiary, and quaternary. The primary structure of the protein has been known to have peptide bonds. Thus, option C is correct.

<h3>What are peptide bonds?</h3>

Peptide bonds are the chemical bonds that are involved in protein polymer formation by linking the amino acid chains. They are also called amide bonds that are present between the nitrogen and the carbonyl atom.

The primary structure of the proteins includes the amino linked by the peptide bonds that make them look like linear structures. The secondary structures have hydrogen bonds and the tertiary have ionic and hydrophilic hydrogen bonds.

Therefore, option C. the primary structure of the protein contains peptide bonds.

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6 0
2 years ago
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