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Maru [420]
3 years ago
8

Find the sum:(11x+3)+(x+-5)

Mathematics
1 answer:
VikaD [51]3 years ago
6 0

Answer:

12−2

Step-by-step explanation:

Simplify,

(11+3)+(−5)

11+3+−5

Subtract,

11+3+−5

11−2+

Combine like terms,

11−2+

12−2

Since we can't go any further, the solution is,

12−2

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Find 5 points that satisfy the equation y= 12+2x
Goshia [24]
We start by finding the intercept of the line: what does y equal when x=0? and what does x equal when y=0?
• intercept in x
y = 12 + 2x
0 = 12 + 2x
-12 = 2x
-6 = x
• intercept in y
y = 12 + 2x
y = 12 + 2(0)
y = 12 + 0
y = 12
Now we find three more points giving y a value and finding x
y = 12 + 2x
2 = 12 + 2x
2-12 = 2x
-10 = 2x
-5 = x

y = 12 + 2x
6 = 12 + 2x
6 - 12 = 2x
-6 = 2x
-3 = x

y = 12 + 2x
14 = 12 + 2x
14 - 12 = 2x
2 = 2x
1 = x

Notice how I gave y even numbers as values since we would have to divide with 2 at the end.

Sol. {(-6,0)(0,12)(-5,2)(-3,6)(1,14)}
8 0
3 years ago
Determine the explicit equation for the arithmetic sequence given below.-3,-7,-11,-15,-19
liraira [26]

Answer:

-3 + (n-1)(-4)

Step-by-step explanation:

We follow the formula.

a1 + (n-1)d

d is the common difference.

7 0
3 years ago
Read 2 more answers
How to solve the second equation
ivann1987 [24]
\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{lccclll}
y = &{{ -0.02}}x^2&{{ +1}}x&{{ +6}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
\\\\\\
\left( -\cfrac{1^2}{2(-0.02)}~~,~~6-\cfrac{1^2}{4(-0.02)} \right)
\\\\\\
(\stackrel{\textit{how far ahead it went}}{25}~,~\stackrel{\textit{how high it went}}{18\frac{1}{2}})

\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{lccclll}
y = &{{ -0.01}}x^2&{{ +0.7}}x&{{ +6}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
\\\\\\
\left( -\cfrac{0.7^2}{2(-0.01)}~~,~~6-\cfrac{0.7^2}{4(-0.01)} \right)
\\\\\\
(\stackrel{\textit{how far ahead it went}}{24\frac{1}{2}}~,~\stackrel{\textit{how high it went}}{18\frac{1}{2}})
4 0
4 years ago
Find the dimensions of a rectangle with a perimeter of 52cm if it’s length is 4cm more than its width
Zina [86]
So the perimeter(P) of a rectangle would be:
P= 2L+2W
L being the length and W being the width.
The problem says the length is 4cm more than the width, so L= 4+W.
So if we substitute L with 4+W, we get:
P= 2(4+W) + 2W
Use the Distributive Property
P= 8+2W+2W
Combine like terms
P=8+4W
Since we're given the perimeter, we could replace P with 52. So:
52=8+4W
Subtract 8 to both sides
44=4W
Divide 4 to both sides
11=W
Therefore, the width is 11cm
And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm
Thus, the dimensions of the rectangle are 15cm by 11cm
5 0
4 years ago
If susan is charged $175, how many days did susan rent A ski lift pass
Fudgin [204]

Answer:

Step-by-step explanation:

three days?

4 0
3 years ago
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