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lara [203]
3 years ago
11

Y'all - please help I have been on this question for like 20 mins

Mathematics
1 answer:
AURORKA [14]3 years ago
5 0

Answer:

d

Step-by-step explanation:

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Answer corecctly plss<br> 7(2+5v0=2v+14
Radda [10]

Answer:

v=0

Step-by-step explanation:

I think you mean 7(2+5v)=2v+14.

14+35v=2v+14 distribute

33v=0  Subtract 2v and 14

v=0 divide by 33 on both sides

Hope this helps plz mark brainliest if correct :D

7 0
3 years ago
Prove that 12^13-12^12 is divisible by 7
Svet_ta [14]
When you use PEMDAS you end up with the answer of 12. 12 can’t be divided by 7 so 12^13-12^12 is not divisible by 7
3 0
3 years ago
Read 2 more answers
Four students explain how to find the measure of ZRST in this diagram.
TEA [102]

Answer:

To find the angle RST we have to first find SRT As the exterior angle adjoined with SRT =53°

so the SRT = Outer angle adjoined with angle SRT

angle SRT = 53° [°.° vertically opposite angles are equal]

Angle SRT + Angle STR + Angle RST = 180°

=>53° + 75° + Angle RST =180°

=> 128° + Angle RST = 180°

=> Angle RST =(180-128)°

= 52°

SO NO. <em><u>C</u></em> IS correct what Cate says is absolutely right

6 0
3 years ago
If you want to rent bikes for you and your friend and the bike cost $3.25 per hour how much money do you have to have for 5 hour
kirza4 [7]

Answer: if you are paying for you and your friends bike rentals, it is $32.50

Step-by-step explanation:

3.25x10 (2)

5 0
3 years ago
a study of nickels showed that the standard deviation of the weight of nickels is 300 milligrams. A coin counter manufacture wis
cupoosta [38]

Using the z-distribution, a sample of 609 nickels has to be weighed.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

For this problem, the parameters are:

M = 20, \sigma = 300, z = 1.645

We solve for n to find the sample size, then:

M = z\frac{\sigma}{\sqrt{n}}

20 = 1.645\frac{300}{\sqrt{n}}

20\sqrt{n} = 1.645 \times 300

\sqrt{n} = 1.645 \times 15

(\sqrt{n})^2 = (1.645 \times 15)^2

n = 608.9

Rounding up, a sample of 609 nickels has to be weighed.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

6 0
2 years ago
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