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Pepsi [2]
3 years ago
5

Peter works as a delivery person for a bike shipping company. The graph shows a linear model for his

Mathematics
1 answer:
evablogger [386]3 years ago
6 0

Answer/Step-by-step explanation:

a. Using a point on the graph, (6, 12), and the slope of the line, we can first generate an equation in the point-slope form, given as y - b = m(x - a), where,

m = slope, and (a, b) is a point on the line.

Using two points, (6, 12) and (3, 21), let's find slope, m.

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{21 - 12}{3 - 6} = \frac{9}{-3} = -3

Using a point (6, 12) and slope, m = -3, generate an equation in the point-slope form by substituting a = 6, b = 12, and m = -3 in y - b = m(x - a).

✅Equation in point-slope form would be:

y - 12 = -3(x - 6)

Rewrite this to make it be in the slope-intercept form, y = mx + b.

y - 12 = -3(x - 6)

y - 12 = -3x + 18

Add 12 to both sides

y = -3x + 18 + 12

y = -3x + 30

✅The equation in slope-intercept form is y = -3x + 30

b. ✍️Based on the linear model, y = -3x + 30, the 30 represents b = y-intercept.

✅Therefore, it took Peter 30 mins long initially to deliver his package.

✍️Based on the linear model, y = -3x + 30, "-3" represents the slope.

✅Therefore,  Peter's delivery time decreased 3 mins per day.

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Answer:

Both plans last for 1.25 hours (1 hour 15 minutes)

Step-by-step explanation:

Let x hours be the time needed for plan A and y hours be the time needed for plan B.

On Wednesday there were 5 clients who did Plan A and 3 who did Plan B. Thus, 5x+3y=10.

On Thursday there were 2 clients who did Plan A and 6 who did Plan B. Thus, 2x+6y=10.

Solve the sytem of two equation. Multiply the first equation by 2, the second by 5 and subtract them:

10x+6y-10x-30y=20-50,\\ \\-24y=-30,\\ \\y=\dfrac{30}{24}=\dfrac{5}{4}=1.25\ hours.

Therefore,

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Dahasolnce [82]
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3 years ago
Calculate the probability that a particle in a one-dimensional box of length aa is found between 0.29a0.29a and 0.34a0.34a when
Helga [31]

Answer:

P(0.29a < X < 0.34a) = -(4a/π) [(cos 0.34πa²) - (cos 0.29πa²)]

Assuming the box is of unit length, a = 1,

0.29a = 0.29 and 0.34a = 0.34

P(0.29 < X < 0.34) = (-4/π) [(cos 0.34π) - (cos 0.29π)] = 0.167 = 0.17 to 2 s.f

Step-by-step explanation:

ψ(x) = 2a(√sin(πxa)

The probability of finding a particle in a specific position for a given energy level in a one-dimensional box is related to the square of the wavefunction

The probability of finding a particle between two points 0.29a and 0.34a is given mathematically as

P(0.29a < X < 0.34a) = ∫⁰•³⁴ᵃ₀.₂₉ₐ ψ²(x) dx

That is, integrating from 0.29a to 0.34a

ψ²(x) = [2a(√sin(πxa)]² = 4a² sin(πxa)

∫⁰•³⁴ᵃ₀.₂₉ₐ ψ²(x) dx = ∫⁰•³⁴ᵃ₀.₂₉ₐ (4a² sin(πxa)) dx

∫⁰•³⁴ᵃ₀.₂₉ₐ (4a² sin(πxa))

= - [(4a²/πa)cos(πxa)]⁰•³⁴ᵃ₀.₂₉ₐ

- [(4a/π)cos(πxa)]⁰•³⁴ᵃ₀.₂₉ₐ = -(4a/π) [(cos 0.34πa²) - (cos 0.29πa²)]

P(0.29a < X < 0.34a) = -(4a/π) [(cos 0.34πa²) - (cos 0.29πa²)]

Assuming the box is of unit length, a = 1

P(0.29 < X < 0.34) = (-4/π) [(cos 0.34π) - (cos 0.29π)] = (-1.273) [0.482 - 0.613] = 0.167.

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dolphi86 [110]

Answer:

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Step-by-step explanation:

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hope this helps have a great day ツ

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