Answer 28.
Possible values for the three factors of -3
- 1, -1 and 3
- -1.5, 1 and 2
- 1.5, -1 and 2
- 1.5, 1 and -2
Answer 29.
The product of two nonzero integers will be less than or equal to both of the integers if they are multiplied by number itself and one or by number itself and one with negative sign.
Answer 30.
The sign of the product of three integers with the same sign will be positive or negative. If odd number of same sign is multiplied, the product will be of that sign.
(+) (+) (+) = (+)
(-) (-) (-) = (-)
84. Area of a triangle is (base x height) / 2
Answer: i) 1 - 9x² - 12x
ii) 17 - 3x²
iii) - 20 + 10x² - x⁴
<u>Step-by-step explanation:</u>
g(x) = 3x + 2 h(x) = 5 - x²
i) h(g(x))
h(3x + 2) = 5 - (3x + 2)²
= 5 - (9x² + 12x + 4)
= 5 - 9x² - 12x - 4
= 1 - 9x² - 12x
ii) g(h(x))
g(5 - x²) = 3(5 - x²) + 2
= 15 - 3x² + 2
= 17 - 3x²
iii) h(h(x))
h(5 - x²) = 5 - (5 - x²)²
= 5 - (25 - 10x² + x⁴)
= 5 - 25 + 10x² - x⁴
= -20 + 10x² - x⁴
61/100, because if it is 0.(value) than it is value / 100 assuming value is 2 digits long. We cannot simplify it further because 61 is prime number.
Answer:
D = L/k
Step-by-step explanation:
Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is
dA/dt = in flow - out flow
Since litter falls at a constant rate of L grams per square meter per year, in flow = L
Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow
So,
dA/dt = in flow - out flow
dA/dt = L - Ak
Separating the variables, we have
dA/(L - Ak) = dt
Integrating, we have
∫-kdA/-k(L - Ak) = ∫dt
1/k∫-kdA/(L - Ak) = ∫dt
1/k㏑(L - Ak) = t + C
㏑(L - Ak) = kt + kC
㏑(L - Ak) = kt + C' (C' = kC)
taking exponents of both sides, we have
When t = 0, A(0) = 0 (since the forest floor is initially clear)
So, D = R - A =
when t = 0(at initial time), the initial value of D =
