3 are expected to have the condition.
The expected value is the found by multiplying the probability by the number in the sample:
(1/200)×600
= (1/200)×(600/1)
= (1×600)/(200×1)
= 600/200 = 3
Since the number of cats has to be less than 28, a statement could be "the shelter can house no more than 28 cats.
<h3>
Answer: choice A, graph is moved 7 units up</h3>
The plus 7 at the end will shift the graph 7 units up. Replace y with f(x).
Then we have g(x) = f(x) + 7. Adding 7 to y = f(x) will increase the y value by 7.
The problem can be solved step by step, if we know certain basic rules of summation. Following rules assume summation limits are identical.




Armed with the above rules, we can split up the summation into simple terms:





=> (a)
f(x)=28n-n^2=> f'(x)=28-2n
=> at f'(x)=0 => x=14
Since f''(x)=-2 <0 therefore f(14) is a maximum
(b)
f(x) is a maximum when n=14
(c)
the maximum value of f(x) is f(14)=196
They all are all math vocabulary