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marishachu [46]
3 years ago
14

Which statements about experimental probability are true? Select three options. Experimental probability has the total number of

trials in the numerator and the number of times an event occurs in the denominator. Experimental probability is the same as theoretical probability. An experiment to determine probability will include a number of trials. A probability experiment will count the number of times an event occurs. Experimental probability can be written in the form of a ratio.
Mathematics
2 answers:
erma4kov [3.2K]3 years ago
8 0

Answer:

C D E or 345

Step-by-step explanation:

MAVERICK [17]3 years ago
6 0

Answer:

CDE

Step-by-step explanation:

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Answer:

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Simplify the expression 3x(4x^4 - 5x)
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4 years ago
Please help!
crimeas [40]

Answer:

The zeros are:

x =4, x=2, x = 5

  • The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

0=\left(x-4\right)^2\left(x^2-7x+10\right)

switch sides

\left(x-4\right)^2\left(x^2-7x+10\right)=0

as

x^2-7x+\:10=\left(x-2\right)\left(x-5\right)

so

\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0

Using the zero factor principle

  • \mathrm{If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

so

x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x =4, x=2, x = 5

Thus, the zeros are:

x =4, x=2, x = 5

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

  • The function has three distinct real zeros.

Hence, option (B) is true.

4 0
3 years ago
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Y= 3x+7<br> y = -2x-3<br> What would be the x and y for that solution
alexandr402 [8]

Answer:

So if we are solving for x and y. First we need to subtract both equations. We take each equation and put in parenthesis and subtract.

y-y = (3x+7)-(-2x-3) =

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0 = 5x+10

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-2 = x.

Now we need to solve for y.

Plug it in for the first equation. -2*3+7 = -6+7 = 1

Test if we are correct and try in the second equation.

-2*-2-3 = 4-3 = 1

<u>x = -2</u>

<u>y = 1</u>

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