I think you mean to say
. If
is in the third quadrant, then
and
. Recall that
We expect
to be negative, so we take the negative root. We end up with
We also know to expect
, so
By definition, we have
and so
Answer:
45
Step-by-step explanation:
The different pairs of individual can be computed using rule of combination.
The combination is denotes as nCr.
nCr=n!/(r!(n-r)!)
In the given problem n=total candidates=10 and r= Selected candidates=2.
10C2=10!/(2!(10-2)!)
10C2=10*9*8!/(2!8!)
10C2=90/2
10C2=45
So, 45 different pairs of individuals can be selected.
Scalar multiplication of a matrix refers to the
multiplication of all the elements of the matrix by an ordinary number which is
called a scalar.
From the given options the statements which are true about
scalar multiplication of matrices are;
a)
You can
multiply a matrix of any size by a scalar.
b)
For any matrix A, 1 × A = A.
c)
Scalar multiplication is a shortcut for repeated
addition of the same matrix.
I’m not too sure of what the equation is but I made a guess let me know if this was the right equation please I can redo it.
But, when solving this equation you are trying to find the value of x. To do that you have to get rid of the 3.
You would either add or subtract the 3 on both sides.
When the three is gone you should have somthing like
x = 5
- 3
Which you would move on to subtract the 5-3 and get 2.
x= 2
Here’s a picture of how I solved it
