Which one should I choose.
1 answer:
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<h3>The distance covered by Drew in long jump is either 7 ft 5 inches OR 7 ft 6 inches.</h3>
Step-by-step explanation:
Here, the needed table is attached for the reference.
Now, as we can see from the table:
The distance covered by Cindy = 2 yards, 1 foot 3 inches
The distance covered by Tyrette = 7 feet, 2 inches
The distance covered by Nina = 2 yards, 1 foot, 1 inch
The distance covered by Monique = 7 feet, 4 inches
As we know : 1 yard = 3 feet
So, the distance covered by :
Cindy = 2 yards, 1 foot 3 inches = 3 ft x (2) + 1 ft + 3 in = 7 ft 3 in
Tyrette = 7 feet, 2 inches
Nina = 2 yards, 1 foot, 1 inch = = 3 ft x (2) + 1 ft + 1 in = 7 ft 1 in
Monique = 7 feet, 4 inches
So by comparing all distances, we can see that:
The maximum distances jumped by all four is 7 ft 4 inches.
The distance covered by Drew is less than 7 ft 7 in.
So, he must have jumped 7 ft 5 inches OR 7 ft 6 inches.
Hence, the distance covered by Drew in long jump is either 7 ft 5 inches OR 7 ft 6 inches.
To solve for the longest side, the hypotenuse, you have to use the pythagorean theorem. It will be 10^2 + 9^2 = c^2. 100 + 81 =c^2.
c^2 = 181 so c = sqrt(181).
to find sin of A do opposite/hypotenuse which gives you 9/sqrt(181)
to find cos of A do adjacent/hypotenuse which gives you 10/sqrt(181)
c^2 = 181 so c = sqrt(181).
to find sin of A do opposite/hypotenuse which gives you 9/sqrt(181)
to find cos of A do adjacent/hypotenuse which gives you 10/sqrt(181)