The sum of the complex number 12 – 5i and –3 + 4i is 9 - i
<h3>How to sum complex number?</h3>
The sum of 12 – 5i and –3 + 4i can be done as follows:
Therefore,
12 - 5I + (-3 + 4i)
12 - 5i - 3 + 4i
Hence,
combine like terms
12 - 3 - 5i + 4i
Finally,
9 - i
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Answer:
−3y2−8y−12
Step-by-step explanation:
Let's simplify step-by-step.
−5y2−9y−4−(−2y2−y+8)
Distribute the Negative Sign:
=−5y2−9y−4+−1(−2y2−y+8)
=−5y2+−9y+−4+−1(−2y2)+−1(−y)+(−1)(8)
=−5y2+−9y+−4+2y2+y+−8
Combine Like Terms:
=−5y2+−9y+−4+2y2+y+−8
=(−5y2+2y2)+(−9y+y)+(−4+−8)
=−3y2+−8y+−12
Answer:
1.38888888889 Rounded answer: 1.40 or 1.4
Step-by-step explanation:
Answer:
126 minutes
Step-by-step explanation:
Centroid, orthocenter, circumcenter, and incenter are the four locations that commonly concur.
<h3>Explain about the concurrency of medians?</h3>
A segment whose ends are the triangle's vertex and the middle of the other side is called a median of a triangle. A triangle's three medians are parallel to one another. The centroid, also known as the point of concurrency, is always located inside the triangle.
The incenter of a triangle is the location where the three angle bisectors meet. The only point that can be inscribed into the triangle is the center of the circle, which is thus equally distant from each of the triangle's three sides.
Draw the medians BE, CF, and their intersection at point G in the triangle ABC. Create a line from points A through G that crosses BC at point D. We must demonstrate that AD is a median and that medians are contemporaneous at G since AD bisects BC (the centroid)
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